9 days ago

Mr Henderson has 2 bouncy ball vending machines , he buys one bag of the 27 millimeter balls and one bag of the 40 millimeter ba

lls . he puts an equal number of each in the 2 machines how many bouncy balls does he put in each machine ? please answer and explain how u find the answer

Mathematics

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A series contains 18 numbers and has a sum of 4,185. The last number of the series is 275. What is the first number?

Inessa [12570]

The formula for the sum of an arithmetic series is expressed as:
Sn=n/2(a1+an)
where:
n=total terms
a1=the initial term
an=the final term
given
n=18, an=275, Sn=4185
substituting these values into the equation results in:
4185=18/2(a1+275)
after simplification, we obtain:
4185=9(a1+275)
dividing by 9 yields:
465=a1+275
therefore
a1=465-275
a1=190

Conclusion: the first term is 190

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About 400,000 people visited an art museum in December. What could be the exact number of people who visited the art museum

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The precise answer is 359,572.

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3 months ago

Read 2 more answers

The Spirit Team will be selling popcorn as a fundraiser at the next basketball game to earn funds to go to Orlando for a competi

zzz [12365]

Response:1 and 2

Step-by-step Explanation:

Provided data

Volume required $V=220\ in.^3$

For the initial cylinder

$r=3\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_1=\pi (3)^2(4)$

$V_1=113.11\ in^3$

For the second cylinder

$r=4\ in.$

$h=4\ in.$

$V=\pi r^2h$

$V_2=\pi (4)^2(4)$

$V_2=201.08\ in^3$

For the third cylinder

$r=9\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_3=\pi (9)^2(9)$

$V_3=2290.51\ in^3$

For the fourth cylinder

$r=4\ in.$

$h=9\ in.$

$V=\pi r^2h$

$V_4=\pi (4)^2(9)$

$V_4=452.448\ in^3$

Thus, cylinders $1$ and $2$ meet the requirement as they remain under $220\ in.^3$

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3 months ago

We flip a fair coin five times. For every heads you pay me $1 and for every tails I pay you $1. Let X denote the my net winning

AnnZ [12381]

The probability mass function of X equals 0.03. To clarify:
Assuming the requirement for winning is one side as heads and the opposing side as tails, the likelihood of both outcomes is 1/2 or 0.5. Thus, we can construct a graph to calculate all probabilities related to achieving heads. In this context, X indicates the dollar amounts won during the coin flips, while the probability of heads reflects the likelihood of each outcome and the potential winnings. The chances of winning decrease as the winning amount rises.

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