Answer:
The mass of the water removed is 66.67 kg
Step-by-step explanation:
Given data
The solids blended with sugar make up 10%.
Final product achieved = 15% product.
Final product contains = 15% sugar solids.
The initial product weighs = 200 kg
Solution
Here, we find the needed sugar amount as follows:
The amount of sugar required = 200 ×
Thus, the needed sugar = 20 kg
We recognize that total solids = product solids + sugar solids...............1
Also, the initial product equals the final product.
So,
0.20 × 200kg= 0.30 × total mass of the final product
The mass of the final product = 133.33 kg
However,
the final product contains 15% product solids and 15% sugar solids, which means that the amount of product solids equals the sugar solids.
Thus, the mass of water removed = 200 kg - 133.33 kg.
The mass of the water removed is 66.67 kg.
Response: a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318
Detailed explanation:
In Problem 8-4, the computer time-sharing system experiences teleport inquiries at an average rate of 0.1 per millisecond. We are tasked with determining the probabilities of the inquiries over a specific period of 50 milliseconds:
Given that
Applying the Poisson process, we find that
(a) at most 12
probability=
(b) exactly 13
probability=
(c) more than 12
probability=
(d) exactly 20
probability=
(e) within the range of 10 to 15, inclusive
probability=
Thus, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318