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Iteru
9 days ago
8

Add 0.0025 kg, 1750 mg, 2.25 g, and 825,000 μg, and express the answer in grams.

Mathematics
1 answer:
lawyer [4K]9 days ago
8 0

Answer:

6.75g

Step-by-step explanation:

The initial step is to convert all values to grams using rules of three, followed by summation.

In a rule of three calculation, the first step is identifying the measures and how they interrelate; whether their connection is direct or inverse.

In direct relationships, as one measure increases, so does the other.

In inverse relationships, as one measure increases, the other decreases.

Problems involving unit conversion, like this, illustrate a direct relationship between measures.

First step: convert 0.0025kg to grams

One kilogram equals 1000 grams, so:

1kg - 1000g

0.0025kg - xg

x = 1000*0.0025 = 2.5g

Thus, 0.0025kg is equal to 2.5g

Second step: handle 1750 mg

One gram consists of 1000mg, so:

1g - 1000mg

xg - 1750mg

1000x = 1750

x = \frac{1750}{1000}

x = 1.75g

Therefore, 1750 mg converts to 1.75g

2.25g is fine

Third step: convert 825,000 μg to grams

One gram consists of 1,000,000 micrograms, so:

1g - 1,000,000 μg

xg - 825,000 μg

1,000,000x = 825,000

x = \frac{825,000}{1,000,000}

x = 0.25g

So, 825,000 μg equals 0.25g

Final step: sum all values

0.25g + 2.25g + 1.75g + 2.50g = 6.75g

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tester [3938]

Answer: $434, 306.4

Step-by-step explanation:

From the information provided,

P= $163,000

R= 14% ; 14/100= 0.14

T=7 years

Using the formula,

A= Pr e^t

A= 163000*e^(0.14*7)

= 163000*e^(0.98)

= $434,306.4

7 0
14 days ago
The waiting time, in hours, between successive speeders spotted by a radar unit is a continuous ran- dom variable with a cumulat
zzz [4035]

Answer: 0.5507

Step-by-step explanation:

Given: The time between sightings of speeders by a radar system is represented by the continuous random variable X, which follows a cumulative distribution function

F(x)= \begin{cases}0,& x

If we convert 12 minutes into hours, it equals \dfrac{12}{60} hours or 0.2 hours.

To find the probability of waiting less than 12 minutes:

P(X

Thus, the probability we are looking for is: 0.5507

4 0
13 days ago
Eric plays basketball and volleyball for a total of 95 minutes every day. He plays basketball for 25 minutes longer than he play
lawyer [4039]

Answer:

Part A:

x+y= 95

x = y+25

Part B: 35 minutes

Part C: No

Step-by-step explanation:

  • Part A:

Eric spends a total of 95 minutes daily playing basketball and volleyball combined.

x+y= 95

Where:

x =minutes Eric plays basketball

y = minutes he allocates to volleyball

He dedicates 25 minutes more to basketball compared to volleyball.

x = y+25

Equations are:

x+y= 95

x = y+25

  • Part B:

Substituting x=y+25 into the first equation yields:

(y+25) + y =95

Solving for y

y+25+y =95

25+2y=95

2y=95-25

2y=70

y = 70/2

y = 35 minutes

Part C: No

If x = 35

x+y= 95

35+y =95

y= 95-35

y = 60 minutes

Inserting y=60 into the other equation:

x = y+25

35 = 60+25

35 ≠85

5 0
9 days ago
What is the simplified form of the following expression ? Assume a _>0 and c >_0
tester [3938]
14 \sqrt[4]{a^{5} b^{2 }c^{4}} -7ac \sqrt[4]{a b^{2}}
= 14ac \sqrt[4]{a b^{2}} -7ac \sqrt[4]{a b^{2}}
= 7ac \sqrt[4]{a b^{2}}.... pertains to the first choice
3 0
20 hours ago
Read 2 more answers
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
Svet_ta [4341]

Answer:

The shaped region accounts for 7/18 of the area of ACIG.

Step-by-step explanation:

Refer to the attached diagram for further clarity on the problem.

Step 1

Determine the length of one side of square ABED.

We know that

AB=BE=ED=AD

The area of a square can be calculated as

A=b^{2}

where b is the side length.

We have

A=49\ units^2

So we substitute

49=b^{2}

b=7\ units

Thus,

AB=BE=ED=AD=7\ units

Step 2

Calculate the area of ACIG.

The area of rectangle ACIG is determined by

A=(AC)(AG)

Substituting the given values yields

A=(9)(10)=90\ units^2

Step 3

Determine the area of the shaded rectangle DEHG.

The area of rectangle DEHG is given by

A=(DE)(DG)

We find DE=7\ units

DG=AG-AD=9-7=2\ units

and substitute A=(7)(2)=14\ units^2

Step 4

Calculate the area of shaded rectangle BCFE.

The area of rectangle BCFE equals

A=(EF)(CF)

We see that

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

and substitute

A=(3)(7)=21\ units^2

Step 5

Add the areas of the shaded regions together.

14+21=35\ units^2

Step 6

Divide the area of the shaded region by the area of ACIG.

\frac{35}{90}

Simplify this fraction by dividing both the numerator and denominator by 5.

\frac{7}{18}

Hence, the shaped region represents 7/18 of the area of ACIG.

5 0
7 days ago
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