Response with clarification:
Let p denote the proportion of adults in the town who have encountered this flu strain.
According to the provided information

∵
this is a two-tailed test.
Test statistic:

, where p= denotes the population proportion
= signifies the sample proportion
n= represents the sample size
Setting n= 6 and
and p=0.08


P-value for the two-tailed test:[2P(Z>|z|)
=2P(Z>|-0.415|)
=2P(Z>0.415) = 2[1-P(Z≤0.415)] [∵ P(Z>z)=1-P(Z≤z)]
=2(1-0.6609) [from the z-table]
=0.6782
Decision: Because the p-value(0.6782) exceeds the significance level of 0.01, we do not reject the null hypothesis.
This leads us to conclude that there is insufficient evidence to back the assertion that the percentage of all adults in this town exposed to this flu strain deviates from the national average of 8%.
Response:
the solution can be found in the image
The probability mass function of X equals 0.03. To clarify:
Assuming the requirement for winning is one side as heads and the opposing side as tails, the likelihood of both outcomes is 1/2 or 0.5. Thus, we can construct a graph to calculate all probabilities related to achieving heads. In this context, X indicates the dollar amounts won during the coin flips, while the probability of heads reflects the likelihood of each outcome and the potential winnings. The chances of winning decrease as the winning amount rises.