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Dmitrij
3 days ago
8

Caleb has 76 apples. He wants to bake as many pies as he can. If it takes 8 apples to make each pie, how many apples will he use

? How many apples will not be used?
Mathematics
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Sarah and her children went into a movie theater and she bought $35.50 worth of drinks and candies. Each drink costs $5 and each
AnnZ [12381]

Answer:

Sarah purchased 2 drinks and 6 candies.

Step-by-step explanation:

Let

x ----> the quantity of drinks Sarah bought.

y ----> the number of candies acquired by Sarah.

We know that

the total spent on drinks and candies was $35.50

therefore,

5x+4.25y=35.50 -----> equation A

She bought 3 times more candies compared to drinks.

thus,

y=3x -----> equation B

To resolve the equations graphically

The solution lies at the intersection of the two graphs

utilizing a graphing tool

The result is the coordinate (2,6)

therefore,

Sarah bought 2 drinks and 6 candies.

4 0
3 months ago
How much of a 90% alloy must be combined with 70% gold alloy in order to get 60 ounces of an 85% gold alloy?
Leona [12618]
Let X be the amount of 90% alloy and Y be the amount of 70% alloy. The equations are: x + y = 60  0.9x + 0.7y = 0.85 * 60 By substituting, we have: 0.9x + 0.7(60 - x) = 0.85 * 60 This simplifies to: (0.9 - 0.7)x = (0.85 - 0.7)*60 Solving for x yields: x = (0.85 - 0.7)*60/(0.9 - 0.7) x = 45 ounces For Y, we find: y = 60 - 45 y = 15 ounces
4 0
1 month ago
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to custome
Svet_ta [12734]

Answer:

To inspect a batch consisting of 20 semiconductor chips, a sample of 3 is selected. Out of these, 10 chips fail to meet customer specifications.

a) Total distinct samples possible = 20C3 =  \frac{20!}{3!(17!)} =1140

b) For exactly 2 good chips and 1 bad chip

Total samples = 10C2 * 10C1 = 45 * 10 =450

c) Combinations of 2 good 1 bad, 1 good 2 bad, and 3 bad chips

Total samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3

= 450+450+120=1020

6 0
2 months ago
A point x is 34m due to east of a point Y . The bearing of a flagpole from x and Y are N18°W And N40°E respectively .
Inessa [12570]
The distance from point Y to the flag post measures 38.13 m. Step-by-step explanation: Assuming point Y is located at the intersection of both lines shown. Point X is positioned 34 meters east of point Y. The flagpole at point X is observed at a bearing of N18°W, meaning it creates an angle of 18° to the west from the north at point X. Conversely, at point Y, the flagpole has a bearing of N40°E, which makes a 40° angle towards the east from the north. Considering ∆ AXY as a right triangle, the angle FXY is established. Then, concerning ∆ BYX as another right triangle, the angle FYX is also determined. To find the third angle ∠YFX in triangle FYX, the angle sum property of triangles can be applied: ∠YFX + ∠FYX + ∠FXY = 180° Thus, we have: ∠YFX + 50° + 72° = 180° leading to ∠YFX = 58°. Now we can calculate the distance FY using the sine rule.
7 0
1 month ago
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