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Alona
24 days ago
8

2 sandwiches and 3 croissants costs £11.

Mathematics
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Micah rows his boat on a river 4.48 miles downstream, with the current , 0.32 hours. He rows back upstream the same distance, ag
AnnZ [12381]
Short Answer: Current speed = 3 miles per hour. Given details for downstream distance of 4.48 miles at time 0.32 hours and upstream distance of the same 4.48 miles taking 0.56 hours. Using the equation d = r*t, we equate distances for both directions leading to a function in terms of the current speed. With each correction to solve ultimately yields the current speed as 3 mph.
5 0
3 months ago
A rectangle is transformed according to the rule R0, 90º. The image of the rectangle has vertices located at R'(–4, 4), S'(–4, 1
babunello [11817]
We understand that a rectangle has been altered into the one shown in Figure 1 using this rule:

R_0, \ 90^{\circ}

It is known that the origin is the center of rotation and two rules apply to perform a rotation of 90 degrees, namely:

1. Clockwise

The rule to convert a point in this case is:

(x,y) \rightarrow (y,-x)

This rule has already been implemented to create the image, so we need to reverse the outcome using this formula, hence:

For \ Q(-3,4): \\ \\ (y,-x)=(-3,4) \\ \\ \therefore y=-3 \ and \ -x=4 \therefore x=-4 \\ \\ Thus, \ the \ point \ is: \\ \\ \boxed{Q(-4,-3)}

2. Counterc
lockwise

Applying the same concept as before but with new rules for the scenario:

(x,y) \rightarrow (-y,x)

Reversing the outcome gives us:

For \ Q(-3,4): \\ \\ (-y,x)=(-3,4) \\ \\ \therefore -y=-3 \therefore y=3 \ and \ x=4 \\ \\ Thus, \ the \ point \ is: \\ \\ \boxed{Q(4,3)}

3 0
2 months ago
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Triangle JKL is equilateral. One side of the triangle, JL, is a diameter of circle M. Which is true about line segments JK and K
Inessa [12570]
It can be deduced that because line JL serves as a diameter for a circle, lines JK and KL function as the tangents of that circle. A tangent is defined as "a line that touches a curve at a singular point without intersecting it." Thus, both lines contact the perimeter of circle M, confirming they are tangents.
7 0
2 months ago
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