In ΔIJK, i = 340 cm, ∠I=120° and ∠J=59°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.

Which of the segments listed is not tangent to circle A?

Response:

Average = 2000

Step-by-step breakdown:

The numbers provided are:

1,000 2,300 2,600

To calculate the average:

Initially, round each number to the nearest 1000, then determine the average.

Solution:

1000 is already rounded, so it stays the same.

To round to the nearest thousand, check the hundred's digit.

• If the hundred’s digit exceeds 5, the thousand’s digit increases by 1, and the hundred’s digit is set to 0.

• If it’s less than 5, the thousand’s digit remains the same, changing the hundred’s digit to 0.

Thus, 2300 rounds to 2000.

and 2600 rounds to 3000.

Consequently, the numbers for averaging are 1000, 2000, 3000.

The formula for average is as follows:

upon applying the formula:

So, the average after rounding to the nearest 1000 is 2000.

La familia Freeman:
13 c/kWh (400 kWh) + 2 c/kWh (400 kWh) + 14.5 c/kWh) 450 kWh
 = 6464.5 c
6464.5 c x 30 = 193935

La familia Baum:
8.5 (400) + 12 (400) + 14.5 (450)
= 14725 c

<span>La familia Freeman tiene un costo de $260.83 más que la familia Baum.
</span>

Answer:

Let the train's speed be denoted as x km/h.

Scenario 1:

Distance = 288 km

Speed = x km/h

Time = Distance divided by Speed

= 288/x hours

Scenario 2:

Distance = 288 km

Speed = (x + 4) km/h

Time = 288/(x + 4) hours

As 288/x is greater than 288/(x + 4)

288/x - 288/(x + 4) = 1

288[1/x - 1/(x + 4)] = 1

[x + 4 - x] / [x(x + 4)] = 1/288

[4 / (x^2 + 4x)] = 1/288

x² + 4x = 1152

x² + 4x - 1152 = 0

x² + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0, x - 32 = 0

x = -36, x = 32

x = -36 is not valid as speed cannot be negative.

Conclusively, the train's speed = 32 km/h