A net force is applied on a 100 kg rocket which causes the rocket to acceleration at 10 m/s2. The same net force is applied on a

If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?

serg [3582]

Answer:

$2.5\cdot 10^{-4}$

Explanation:

Strain is defined as the ratio of an object's dimensional change when subjected to a force:

$S=\frac{\Delta L}{L_0}$

where

$\Delta L$ indicates the alteration in length of the object

$L_0$ signifies the object's initial length

In this case, we have $L_0 = 4 m$ and $\Delta L=1 mm=0.001 m$ , hence the strain is

$S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}$

5 0

2 months ago

A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 245 Hz. A person on the pl

Keith_Richards [3271]

through the Doppler effect. The formula for apparent frequency is derived as F apparent = F real x (Vair ± Vobserver) / (Vair ± Vsource). In this scenario, should the observer move towards the source—place a positive sign in the numerator and a negative in the denominator. Since the observer approaches the wall, we apply the formula to derive the necessary speed.

4 0

2 months ago

A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i

Sav [3153]

The force that the car applies on the truck will be 6000 N in the reverse direction.

As per the information provided, the car's mass is one-fourth that of the truck

The truck exerts a force of 6000 N onto the car

We aim to determine the force that the car exerts on the truck

According to Newton's third law, every action has an equal and opposite reaction

Hence, the force from the car on the truck is 6000 N in the opposite direction

7 0

2 months ago

When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup

Sav [3153]

Answer:

$W_f = 148.17J$

Explanation:

The friction created between the tire and the ground generates thermal energy as force is applied during skidding.

The mentioned force relates to half the impact on the rear tire, resulting in a calculated normal force of,

$N=\frac{mg}{2} = \frac{90*9.8}{2} = 441N$

The work executed is determined by the frictional force and the distance covered,

$W_f = fd = \mu_k Nd$

Where $\mu_k [/ tex] is the coefficient of kinetic frictionN is the normal force previously found d is the distance traveled,Replacing,[tex]W_f = (0.80)(441)(0.42)$

The thermal energy produced from the work done is,

$W_f = 148.17J$

3 0

3 months ago