When you skid to a stop on your bike, you can significantly heat the small patch of tire that rubs against the road surface. Sup
1 answer:
Answer:
Explanation:
The friction created between the tire and the ground generates thermal energy as force is applied during skidding.
The mentioned force relates to half the impact on the rear tire, resulting in a calculated normal force of,
The work executed is determined by the frictional force and the distance covered,
Where
The thermal energy produced from the work done is,
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Answer:
Speeds of 1.83 m/s and 6.83 m/s
Explanation:
Based on the law of conservation of momentum,
where m represents mass,
is the initial speed before impact,
and
are the velocities of the impacted object after the collision and of the originally stationary object after the impact.
Thus,
After the collision, the kinetic energy doubles, therefore:
Substituting the initial velocity of 5 m/s provides the equation needed to proceed.
We know that
leads to
Using the quadratic formula leads us to solve for the speeds after the explosion, specifically where a=2, b=-10, and c=-25.
By substituting the values, the solution yields results for the speeds of the blocks, which are ultimately 1.83 m/s and 6.83 m/s.
1) The wave's period remains constant across different media
2) The wave's velocity varies depending on the medium it travels through
3) As a wave transitions between media, its speed, direction, and wavelength can change, while its frequency stays unchanged
Clarification:
1)
The period of a wave signifies the duration it takes for one full oscillation.
The wave's period is the inverse of its frequency:
where
T denotes the period
f is the frequency
The provided table illustrates that the frequency remains consistent across the three media; hence, the period is unchanged as it solely relies on frequency. We can compute it as we know that
f = 350 Hz
thus the period equals
2)
The velocity of a wave can be derived from the wave equation:
where
f indicates the frequency
is the wavelength
, resulting in a speed of
In the second medium,
, leading to a speed of
In the third medium,
, showing a speed of
As a result, we conclude that the wave's speed varies with the medium.
3)
<pwhen a="" wave="" shifts="" from="" one="" medium="" to="" another="" the="" following="" occurs:="">- The wave's direction alters. Specifically, if the subsequent medium is of greater optical density, the wave bends towards the normal; conversely, it bends away if the second medium is of lesser optical density.
- The wave's speed is affected. The wave decelerates in media with higher optical density and accelerates in those with lower optical density.
- The wave's frequency remains unchanged.
- Ultimately, the wave's wavelength is modified. If moving into a medium of greater optical density, the wavelength decreases, while it increases in one of lower optical density.
Discover more about waves here:
</pwhen></pin>Answer:
Explanation:
Aby obiekt był w spoczynku na nachyleniu, wynikowa siła działająca na niego musi wynosić zero. Równanie sił działających w kierunku równoległym do nachylenia jest następujące:
(1)
gdzie
to składowa ciężaru równoległa do nachylenia, przy czym m oznacza masę obiektu, g oznacza przyspieszenie grawitacyjne, a
to kąt nachylenia
to siła tarcia, z
jako współczynnikiem tarcia oraz R jako reakcją normalną nachylenia
Równanie sił w kierunku prostopadłym do nachylenia to
gdzie
R to reakcja normalna
to składowa ciężaru prostopadła do nachylenia
Obliczając R,
I podstawiając do (1)
Rearanżując równanie,
To jest warunek, przy którym równowaga jest zachowana: gdy tangens kąta staje się większy niż wartość , siła tarcia nie jest w stanie zrównoważyć składowej ciężaru równoległej do nachylenia, dlatego obiekt zaczyna zsuwać się w dół.