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Eva8
2 days ago
15

An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

zen is cracked. Assume each egg load is an independent event.
(a) What is the distribution of cracked eggs per dozen ? Include parame-ter values.

(b) What is the probability that a carton of a dozen eggs results in more than one cracked egg ?

(c) Approximate the probability that among 100 dozen of eggs (i.e. 1200 eggs), there will be at most 1 cracked egg in total.

(d) What is the probability that we need more than 100 loaded eggs to observed a cracked egg?
Mathematics
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Dorrian graphed the distance, y, traveled by 2 bikes in x seconds. If the two bikes are racing a distance of 100 feet, which bik
AnnZ [12381]

Response:

The bike positioned higher on the y-axis is the one that has traveled a greater distance.

Step-by-step explanation:

If Dorrian charted the positions of the bikes with time in seconds on the x-axis and distance traveled on the y-axis, the x-coordinates for both bikes would align.

However, the bike that finished faster would achieve a higher y-coordinate, while the slower one trail behind with a lower y-coordinate.

Thus, the bike with the higher y-coordinate is the victor of the race.

6 0
2 months ago
Read 2 more answers
If m<9=97° and m<12=114°, find each measure. I have to show my work.
Leona [12618]

Solution/Step-by-step breakdown:

Information provided:

m<9 = 97°

m<12 = 114°

a. m<1 = m<9 because they are corresponding angles, which are equal.

m<1 = 97° (using substitution)

b. m<2 + m<1 = 180° (since they form a linear pair)

m<2 + 97° = 180° (substitute the value)

m<2 = 180 - 97 (subtracting 97 from both sides)

m<2 = 83°

c. m<3 = m<11 (as they are corresponding angles)

m<11 + m<12 = 180° (linear pair)

m<11 + 114° = 180° (substituting the known angle)

m<11 = 180 - 114

m<11 = 66°

m<3 = m<11 = 66°

d. m<4 + m<3 = 180° (linear pair)

m<4 + 66° = 180° (substituting the known angle)

m<4 = 180 - 66

m<4 = 114°

e. m<5 = m<2 as vertical angles are equal.

m<5 = 83° (using substitution)

f. m<6 = m<1 (vertical angles are equal)

m<6 = 97° (using substitution)

g. m<7 = m<4 (as vertical angles are equal)

m<7 = 114° (using substitution)

h. m<8 = m<3 (due to vertical angles being equal)

m<8 = 66° (using substitution)

i. m<10 = m<2 (corresponding angles are equal)

m<10 = 83° (using substitution)

j. m<11 = m<3 (because they are vertical angles)

m<11 = 66° (using substitution)

k. m<13 = m<5 (corresponding angles)

m<13 = 83° (applying substitution)

l. m<14 = m<9 (as vertical angles)

m<14 = 97° (applying substitution)

m. m<15 = m<12 (as vertical angles)

m<15 = 114° (applying substitution)

n. m<16 = m<11 (because they are vertical angles)

m<16 = 66° (applying substitution)

3 0
2 months ago
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