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Lerok
1 day ago
13

A medication states that the odds of having an allergic reaction are 1 in 50. What is that probability states as a percent?

Mathematics
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Lawrence found a shirt he liked in the clearance aisle for 15% off the original price. If the original price of the shirt was $3
Leona [12618]
The answer is C. Explanation: The shirt originally priced at $35 has a discount of 15%. Therefore, the savings amount will be calculated accordingly.
8 0
2 months ago
The Spirit Team will be selling popcorn as a fundraiser at the next basketball game to earn funds to go to Orlando for a competi
zzz [12365]

Response:1 and 2

Step-by-step Explanation:

Provided data

Volume required V=220\ in.^3

For the initial cylinder

r=3\ in.

h=4\ in.

V=\pi r^2h

V_1=\pi (3)^2(4)

V_1=113.11\ in^3

For the second cylinder

r=4\ in.

h=4\ in.

V=\pi r^2h

V_2=\pi (4)^2(4)

V_2=201.08\ in^3

For the third cylinder

r=9\ in.

h=9\ in.

V=\pi r^2h

V_3=\pi (9)^2(9)

V_3=2290.51\ in^3

For the fourth cylinder

r=4\ in.

h=9\ in.

V=\pi r^2h

V_4=\pi (4)^2(9)

V_4=452.448\ in^3

Thus, cylinders 1 and 2 meet the requirement as they remain under 220\ in.^3

3 0
3 months ago
Terrence walks at a pace of 2 mi/h to the theater and watches a movie for 2 hours and 15 min he rides a bus back home at 40 mi/h
zzz [12365]

Solution:

Let x be the distance in miles from the house to the theater.

Total time taken for the trip =3.5-2.25=1.25 Hr

Then average speed =\frac{Distance}{Time}= \frac{2x}{1.25}\\

Terrence walks at a speed of 2 miles per hour to the theater and returns home at 40 miles per hour.

Thus, Average Speed =\frac{2+40}{2}= 21\\ mi/hr

Both average speeds must be equivalent. Hence, we can express this as:

\frac{2x}{1.25}=21\\
\\
2x=1.25*21\\
\\
x=13.125\\

Consequently, the distance from home is 13.125 miles.

4 0
3 months ago
A space probe is controlled by 7 different instructions from the ground. the probabilities of sending these instructions vary -
Zina [12379]
The space probe must be able to recognize 7 distinct command types.
The number of combinations that can be encoded using n bits is 2^n. Thus, the minimum number of bits required to encode at least 7 different commands would be:

2^n > 7
2^n > 2^2.80
n > 2.80
n=3

A minimum of 3 bits is required
4 0
2 months ago
Read 2 more answers
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