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Liula
16 days ago
10

Given: ∠ABC ≅ ∠DEF and ∠GHI ≅ ∠DEF Prove: m∠ABC = m∠GHI We are given that angle ABC and are congruent, and that angle GHI and an

gle DEF are congruent. By the , the measure of angle ABC is equal to the measure of angle DEF, and the measure of angle GHI is equal to the measure of angle DEF. By the substitution property, the measure of angle ABC is equal to .
Mathematics
1 answer:
AnnZ [3.8K]16 days ago
6 0

1. Angle DEF

2. Definition of congruent angles

3. Measure of angle GHI

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What is the following quotient? StartFraction StartRoot 6 EndRoot + StartRoot 11 EndRoot Over StartRoot 5 EndRoot + StartRoot 3
babunello [3635]

Answer:

StartFraction StartRoot 30 EndRoot minus 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot minus StartRoot 33 EndRoot Over 2

Step-by-step explanation:

We are given the surdic equation depicted in \frac{\sqrt{6}+\sqrt{11} }{\sqrt{5}+\sqrt{3} }\\.

To calculate the quotient, we will rationalize by multiplying both the numerator and denominator of the function by the conjugate of the denominator.

The denominator shown in \sqrt{5}+\sqrt{3} has a conjugate of \sqrt{5}-\sqrt{3}.

After multiplying by \sqrt{5}-\sqrt{3}, we achieve;

= \frac{\sqrt{6}+\sqrt{11} }{\sqrt{5}+\sqrt{3} } * \frac{\sqrt{5}-\sqrt{3} }{\sqrt{5}-\sqrt{3} }\\

= \frac{\sqrt{30}- \sqrt{18}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- \sqrt{9*2}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- 3\sqrt{2}+\sqrt{55}-\sqrt{33}}{2}

The resulting expression provides the needed answer.

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9 days ago
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This Venn diagram shows the pizza topping preferences for 9 students
Inessa [3907]

Answer:

D

Step-by-step explanation:

Six students prefer either pepperoni or olives:

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P (A or B) = 6/9 = 2/3

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The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
zzz [4022]

Answer:

A.) 1508; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

The general equation for an exponential model is:

A = A0e^rt

A0 represents the initial population

A indicates the final population

r is the growth rate; t denotes time

1)

Considering the years 1750 and 1800

Time interval, t = 1800 - 1750 = 50 years

Starting population = 790

End population = 980

To find the growth rate:

980 = 790e^50r

980/790 = e^50r

Applying the natural logarithm to both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this growth rate, let's forecast the population for 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788; approximately 1508 million people

In 1950:

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467; around 1870 million people

2.)

Exponential model from 1800 to 1850

Initial population in 1800 = 980

Final population in 1850 = 1260

t = 1850 - 1800 = 50

Utilizing the exponential equation, we find the growth rate:

1260 = 980e^50r

1260/980 = e^50r

Taking the natural logarithm of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Utilizing this model, the anticipated population in 1950:

In 1950:

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571; approximately 2083 million people

3.)

For 1900: 1650,

For 1950: 2560

t = 1900 - 1950 = 50

Utilizing the exponential formula, we derive the growth rate:

2560 = 1650e^50r

2560/1650 = e^50r

Logarithm both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using this model, the projected population for 2000:

In 2000:

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787; approximately 3972 million people

3 0
2 days ago
What was the name of Jupiter’s big pet dog
AnnZ [3877]
Great Red Spot
Why does this joke keep lingering in my mind??
8 0
15 days ago
If EF bisects CD, CG = 5x-1, GD = 7x-13, EF=6x-4, and GF = 13, find EG (MUST SHOW WORK)
AnnZ [3877]

Answer:

EG = 19

Explanation:

We have a line segment CD that is bisected at point G by EF.

The length CG is expressed as 5x - 1,

while GD measures 7x - 13.

Since G bisects CD, these lengths are equal, so:

5x - 1 = 7x - 13

Solving for x,

2x = 12

x = 6

Further, EF equals 6x - 4, and GF is 13.

Because EF = EG + GF,

we write 6x - 4 = EG + 13

Rearranged, EG = 6x - 17

Substituting x = 6,

EG = 6*6 - 17

EG = 19

This is the final value.

I hope this helps you understand the solution.

3 0
18 days ago
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