Given: ∠ABC ≅ ∠DEF and ∠GHI ≅ ∠DEF Prove: m∠ABC = m∠GHI We are given that angle ABC and are congruent, and that angle GHI and an

Answer:

Step-by-step explanation:

Let x represent the speed of the first ferry.

Consequently, the second ferry's speed is x-5, as it travels 5 miles per hour slower.

The time taken by the first ferry is calculated as distance divided by speed =

The time taken by the second ferry equals .

Since the second ferry departs one hour earlier, the times differ by 1 hour.

The speed cannot be negative.

Thus, the speed of the first ferry is determined to be 18.5 mph,

and for the second, slower ferry, it equals 13.5 mph.

Answer:

The value equals 1

Step-by-step explanation:

Consider the expression

Recall that

For two complementary angles A and B (where A+B=90°),

the identity is

cos(A) = sin(B)

Here, 26° and 64° are complementary angles, so

Substituting values,

From this, we find

By substitution,

Answer:

The correct options are:

The term 5x³ can be removed

The power of the first term, 5x³, can be modified to 2 and combined with the second term, 2x²

Explanation:

The degree of an expression is identified by its highest exponent.

The expression in question is:

5x³ + 2x² + 7x - 3

Observing this, we see that the highest exponent is 3, indicating that the expression’s degree is 3.

A quadratic function is defined as having degree 2, meaning the highest degree must be 2.

Thus, Martha must eliminate the term with degree 3 (5x³) from her function.

This can be achieved through two methods:

1- She can simply remove the term with the third degree.

2- She can change the term with degree 3 to a lower degree and combine it with an existing like term.

Evaluating the options, we conclude the two accurate choices are:

- The term 5x³ can be eliminated.

- The exponent on the first term, 5x³, can be reduced to 2 and subsequently joined with the second term, 2x².

I hope this is helpful!:)

Approximate length of wire ≈ 193 ft (to the nearest foot).

Greetings: 
<span>x² + y² + 8x + 22y + 37 = 0
(x² +8x) +(y² +22y) +37 = 0

</span>(x² +8x+4²)-4² +(y² +22y+11²) -11²+37 = 0
(x+4)² +(y+11)²-16-121+37 =0

(x+4)² +(y+11)² =10²...(<span>standard form )
</span><span>The circle's center is located at (-4, -11) and has a radius of 10</span>