A middle school chess club has 5 members: Adam, Bradley, Carol, Dave, and Ella. Two students from the club will be selected at r
1 answer:
Answer:
The chance of choosing Adam and Ella:
Detailed explanation:
Probabilities
The likelihood of an event E occurring is a figure that ranges between 0 and 1, including both ends, where 0 means the event cannot happen and 1 indicates the event will definitely occur. Various methods exist to calculate probabilities based on the specific context and distribution involved.
This issue can be addressed through basic computations and reasoning due to its straightforward nature. We recognize that the middle school chess club consists of 5 members: Adam, Bradley, Carol, Dave, and Ella. Two members will be randomly chosen to take part in the county chess tournament. We can determine the number of different ways this selection can happen without any limitations. This is referred to as the sample space.
The sample space for this situation involves all combinations of the 5 members without regard for order. Representing the members as {a,b,c,d,e}, the potential combinations are {ab,ac,ad,ae,bc,bd,be,cd,ce,de}. It is important to note that there are exactly 10 combinations because selecting ab is the same as selecting ba, as they form the same team for the competition.
The combination featuring specific members out of the total is just one among the ten. When we designate a=Adam and e=Ella, the only relevant combination is ae, while the remaining 9 do not include both individuals, leading to a probability of
You might be interested in
Answer:
The P-value ranges between 2.5% and 5% according to the t-table.
Step-by-step explanation:
A random sample of 16 students from a large university showed an average age of 25 years with a standard deviation of 2 years.
Let = true average age of all students at the university.
So, the Null Hypothesis, :
24 years {indicating the average age is less than or equal to 24 years}
Alternate Hypothesis, :
> 24 years {indicating the average age is significantly greater than 24 years}
Here we employ the One-sample t-test statistics as the population's standard deviation is unknown;
T.S. = ~
where, = sample average age = 25 years
s = sample standard deviation = 2 years
n = sample size = 16
This gives us the test statistics = ~
= 2
The value of the t-test statistics is 2.
Moreover, the P-value of the test-statistics can be found as follows;
P-value = P( > 2) = 0.034 {as per the t-table}
Thus, the P-value lies between 2.5% and 5% based on the t-table.