Tom Worker pays $900 annually for $60,000 worth of life insurance

Circle D is shown. Line segment F E goes through point D. Line segment C D is shown. Line segment G H goes from one side of the

PIT_PIT [12445]

The answer is Option D: Line G H.

Step-by-step explanation:

Test was conducted on Edge

3 0

2 months ago

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The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a

Leona [12618]

Answer:

The range of cheerleaders' heights lies within the interval [58, 74)

It includes all real numbers from 58 inches and above, but below 74 inches.

Step-by-step explanation:

we have

$260 \leq 4h+28$

Separate the combined inequality into two distinct inequalities

$260 \leq 4h+28$ -----> inequality A

$4h+28$ -----> inequality B

Solve inequality A

$260 \leq 4h+28$

Subtract 28 from both sides

$232 \leq 4h$

Split by 4 on both sides

$58 \leq h$

Reformulate

$h \geq 58\ in$

Address inequality B

$4h+28$

Subtract 28 from both sides

$4h$

Split by 4 on both sides

$h$

consequently

The height range of the cheerleaders is the interval [58, 74)

It consists of every real number starting from 58 inches and less than 74 inches

3 0

3 months ago

A 1500 kg hippo is completely submerged, standing on the bottom of a lake. What is the approximate value of the upward normal fo

zzz [12365]

Answer:

Aproximadamente 428 N

Step-by-step explanation:

Peso = 1,500 * 9.8 = 14,700 N

Densidad = Masa ÷ Volumen

1,030 = 1,500 ÷ V

V = 1,500 ÷ 1,030 = 1.46 m^3.

La fuerza de flotación = Densidad * g * V

La fuerza de flotación = 1,000 * 9.8 * (1,500 ÷ 1,030)

La fuerza de flotación = 9,800 * (1,500 ÷ 1,030) = 14,272 N.

La fuerza neta = 14,700 – [(9,800 * (1,500 ÷ 1,030)]

7 0

3 months ago

Integrated circuits from a certain factory pass a particular quality test with probability 0.75. The outcomes of all tests are m

tester [12383]

Answer:

The anticipated number of tests required to identify 680 acceptable circuits is 907.

Step-by-step explanation:

For any circuit, there are two potential results: it either passes the test or it fails. The likelihood of passing is independent between circuits. Therefore, we apply the binomial probability distribution to address this scenario.

Binomial probability distribution

This distribution calculates the chance of obtaining exactly x successes across n trials, where x has only two possible outcomes.

To find the expected number of trials to achieve r successes with a probability p, the formula is given by:

$E = \frac{r}{p}$

Circuits from a specific factory pass a certain quality evaluation with a probability of 0.75.

Thus, to determine the expected number of tests needed for 680 acceptable circuits, let’s denote this as E where r = 680. $p = 0.75$

$E = \frac{r}{p}$

$E = \frac{680}{0.75}$

$E = 907$

The expected number of tests necessary to find 680 acceptable circuits is 907.

8 0

2 months ago