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Aleks04
16 days ago
12

What values of c and d make the equation true? Assume x greater-than 0 and y greater-than-or-equal-to 0 StartRoot StartFraction

x Superscript 6 Baseline y cubed Over 9 x Superscript 8 Baseline EndFraction EndRoot = StartFraction 5 y Superscript c Baseline StartRoot 2 y EndRoot Over d x EndFraction
Mathematics
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Steve and Ed stand next to each other and throw footballs in the air. The path of Steve’s football is described by the equation
tester [12383]
The question clearly seeks the highest values from both functions, meaning the vertices of each.

<span>The graph depicting the path of Ed’s football indicates the vertex's coordinates (the peak of the graph).
</span>
Specifically,

(h,k) = (1.5, 7.5)

Where (h,k) represents the vertex's location.

Conversely,<span>the trajectory of Steve's football is defined by the equation:
y = - 2x
²</span> + 5x + 4<span>To find the axis of symmetry, we use the formula:x = - b
÷ 2a
Where:

a = -2</span>
b = 5

Consequently,

x = - 5 ÷ - 4

x = 5 / 4




x = 1.25
Now substituting this x-value back into the main equation to determine y.
y = - 2x² + 5x + 4

y = - 2(1.25)² + 5(1.25) + 4

y = - 3.125 + 6.25 + 4


y = 7.125


Thus, the vertex (h,k) = (1.25, 7.125)
As observed from the calculations

Ed’s

<span>football attains a higher height.</span>

5 0
2 months ago
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How many times greater is the value of the 3 in 4,367 than the value of the 3 in 39?​
Inessa [12570]
Approximately 111.97
8 0
2 months ago
2. What is the 44th decimal digit in the decimal representation of 1/11 which equals 0.0909090909
tester [12383]
9. Observing the pattern, the decimal digit at position n is 9 when n is even and 0 when n is odd. Because 44 is an even number, the 44th digit after the decimal point is 9.
6 0
4 months ago
Heights of adult males are known to have a normal distribution. a researcher claims to have randomly selected adult males and me
Leona [12618]

Answer:

The total probability exceeds 100%, indicating a problem with the findings; moreover, the distribution shows excessive uniformity which disqualifies it as a normal distribution.

Detailed explanation:

The sum of probabilities should be exactly 100%. When you add the probabilities of this distribution:

22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121

This exceeds 100%, highlighting a significant error in the results.

A typical normal distribution possesses a bell curve. If we plot the probabilities for this distribution, we'd see bars at 22, 24, 21, 26, and 28.

The bars would fail to form a bell-shaped curve, confirming that this is not a normal distribution.

3 0
3 months ago
Read 2 more answers
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