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slega
2 months ago
15

Steve and Ed stand next to each other and throw footballs in the air. The path of Steve’s football is described by the equation

y = –2x^2 + 5x + 4. The path of Ed’s football is shown by the graph.
In each function, x is the horizontal distance the football travels in meters, and y represents the height.

Whose football reaches a greater height?
A. Steve’s football
B. Ed’s football
C. Both footballs reach the same height.

Mathematics
2 answers:
Inessa [12.5K]2 months ago
6 0
Ed's football

Step-by-step explanation:

tester [12.3K]2 months ago
5 0
The question clearly seeks the highest values from both functions, meaning the vertices of each.

<span>The graph depicting the path of Ed’s football indicates the vertex's coordinates (the peak of the graph).
</span>
Specifically,

(h,k) = (1.5, 7.5)

Where (h,k) represents the vertex's location.

Conversely,<span>the trajectory of Steve's football is defined by the equation:
y = - 2x
²</span> + 5x + 4<span>To find the axis of symmetry, we use the formula:x = - b
÷ 2a
Where:

a = -2</span>
b = 5

Consequently,

x = - 5 ÷ - 4

x = 5 / 4




x = 1.25
Now substituting this x-value back into the main equation to determine y.
y = - 2x² + 5x + 4

y = - 2(1.25)² + 5(1.25) + 4

y = - 3.125 + 6.25 + 4


y = 7.125


Thus, the vertex (h,k) = (1.25, 7.125)
As observed from the calculations

Ed’s

<span>football attains a higher height.</span>

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