Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?

I believe the volume is approximately 1742.54 cm³.

Approximately 2, I believe... I calculated it to be around 2.10. 

Answer:

6.75g

Step-by-step explanation:

The initial step is to convert all values to grams using rules of three, followed by summation.

In a rule of three calculation, the first step is identifying the measures and how they interrelate; whether their connection is direct or inverse.

In direct relationships, as one measure increases, so does the other.

In inverse relationships, as one measure increases, the other decreases.

Problems involving unit conversion, like this, illustrate a direct relationship between measures.

First step: convert 0.0025kg to grams

One kilogram equals 1000 grams, so:

1kg - 1000g

0.0025kg - xg

x = 1000*0.0025 = 2.5g

Thus, 0.0025kg is equal to 2.5g

Second step: handle 1750 mg

One gram consists of 1000mg, so:

1g - 1000mg

xg - 1750mg

1000x = 1750

x = 1.75g

Therefore, 1750 mg converts to 1.75g

2.25g is fine

Third step: convert 825,000 μg to grams

One gram consists of 1,000,000 micrograms, so:

1g - 1,000,000 μg

xg - 825,000 μg

1,000,000x = 825,000

x = 0.25g

So, 825,000 μg equals 0.25g

Final step: sum all values

0.25g + 2.25g + 1.75g + 2.50g = 6.75g

Answer: 0.1289

Step-by-step explanation:

Given: The proportion of students absent on Mondays at a large university.:

Sample size:

Mean:

Standard deviation =

Let x represent a binomial variable.

Referencing the standard normal distribution table,

(1)

Z score for normal distribution:-

For x=4

For x=3

Thus, from (1)

Consequently, the likelihood of four students being absent =

48 divided by 3 equals 16 (cups)
Adding 16 and 16 gives 32 (which is double the number of cups)
Thus, the number of plates is 16.