Add the two expressions. −4.2x+3 and 2.5x−6 Enter your answer in the box.

Response:

Detailed explanation:

We are aware that

She made the trip between her residence and the airport twice.

Therefore,

Multiply the distance from her house to the airport by 4.

a) The area of a rectangle is calculated by multiplying the length by the width:
   A = l·w

This formula allows us to express the width in terms of area and length. By dividing A by l, we find
   A/l = w

We also recognize that the perimeter of a rectangle is the total length around it.
   P = l + w + l + w
   P = 2(l + w)
We aim to rewrite the perimeter formula to isolate l on one side, using the expression for w derived earlier.
   P = 2(l + A/l)

By substituting the known value for A, we can express p(l) as
   p(l) = 2(l + 25/l)
   p(l) = 2l + 50/l


b) For lengths exceeding widths, we have
   l > w
   l > A/l
   l² > A
   l > √A
   l > √25

This indicates that the domain of p(l) is
   l ∈ (5, ∞)..... meters

Answer: Given a population of 500 flies at a certain time we designate as moment , with brown ebony bodies. Assume there are 200 flies with genotype ee, 150 with Ee, and 150 with EE. Calculate the genotype frequencies for this population without leaving any answers as fractions!

The question seems to require answer choices, which are provided below:

a) sqrt(1 - x^2)
<span>b) x / sqrt(1 - x^2)</span>
<span>c) sqrt(1 - x^2) / x</span>
<span>d) 1 / sqrt(1 - x^2)
</span>
The correct selection is <span>c) sqrt(1 - x^2) / x</span>.

This is because cos u equals sqrt(1 - sin² u), which is sqrt(1 - x²), and cot u is defined as cos u divided by sin u.

Answer:

To measure 1.25 mL of dye solution, use 5 mL of dye combined with 3 mL of water

Consequently, the total solution volume reaches 8 mL.

Next,

This 8 mL solution consists of

part dye and

part water.In the following step, extract 2 mL of this solution.

Thus,

The dye content in the 2 mL solution is

or

The 2 mL solution contains 1.25 mL of dye

Hence,

the required 1.25 mL of dye is now accurately measured.

Step-by-step explanation:

Given:

A 10-mL graduated cylinder calibrated in 1-mL increments

The dye solution to be measured = 1.25 mL

Now,

Combine 5 mL of dye with 3 mL of water

This creates a total solution volume of 8 mL.

Next,

This 8 mL solution comprises

part dye and

part water.Then, extract 2 mL from this solution.

Thus,

The concentration of dye in the 2 mL solution measures

or

1.25 mL of dye per 2 mL solution

Therefore,

1.25 mL of dye has been accurately determined.