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andrey2020
15 days ago
10

• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando

m sample of 100 adults, 31% say they use their phone for most of their online browsing. At 1% level of significance, is there enough evidence to support the researcher’s claim?
Mathematics
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A child designs a flag in the shape of a rhombus, as shown in the diagram below. Which expression can be used to determine the s
Zina [12379]
<span>Which formula can be applied to find the side length of the rhombus?

 The correct answer is the first choice: 10/Cos(30°)

 Explanation:

 1. The figure shows a right triangle, where the hypotenuse is denoted by "x," and this is the length you are solving for. Therefore, you have:

 Cos(</span>α)=Adjacent side/Hypotenuse
<span>
 </span>α=30°
<span> Adjacent side=(20 in)/2=10 in
 Hypotenuse=x

 2. Inputting these numbers into the equation yields:
</span>
 Cos(α)=Adjacent side/Hypotenuse
<span> Cos(30°)=10/x

 3. Hence, by isolating the hypotenuse "x," you arrive at the expression to find the side length of the rhombus, as shown below:

 x=10/Cos(30°)
</span>

7 0
2 months ago
A small plane flies 760,320 yards in 2 hours. Use the formula d = rt, where d represents distance, r represents rate, and t repr
tester [12383]

Answer:

Refer to the explanation below.

Step-by-step explanation:

We start with a small aircraft that flies 760,320 yards within a duration of 2 hours.

A)

The formula for distance is:

d=rt

To isolate the rate r, we divide both sides by time:

r=\frac{d}{t}

B)

To calculate the rate in yards per hour, divide the total yards by the hours taken. Therefore:

r=\frac{\text{760320 yards}}{\text{2 hours}}

Perform division:

r=\text{380160 yd/hr}

Thus, the aircraft speeds at 380,160 yards every hour.

C)

There are 1,760 yards in a mile.

To compute the speed in miles per hour, we apply dimensional analysis.

We recognize the rate is 380,160 yards per hour:

r=\frac{\text{380160 yards}}{\text{1 hour}}

To cancel "yards" from the numerator, we multiply by 1 mi/1,760 yards. Therefore:

r=\frac{\text{380160 yards}}{\text{1 hour}}\cdot \frac{\text{1 mi}}{\text{1760 yards}}

This eliminates yards:

r=\frac{\text{380160}}{\text{1 hour}}\cdot \frac{\text{1 mi}}{\text{1760}}

Now, multiply the values across:

r=\frac{\text{380160 mi}}{\text{1760 hour}}

Then divide:

r=\frac{\text{216 miles}}{\text{ hour}}

The final rate for the plane is 216 miles per hour.

D)

Miles are a more appropriate measurement in this context because the distance is substantial, making it impractical to express using yards. A rate of 380,160 yards per hour is excessive, whereas 216 miles per hour provides a clearer understanding.

7 0
3 months ago
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