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MaRussiya
3 months ago
11

10 times as many as 1 ten is ______ tens.

Mathematics
1 answer:
Svet_ta [12.7K]3 months ago
5 0
I suppose it's the same amount as 10 tens.
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You have just opened a new nightclub, Russ' Techno Pitstop, but are unsure of how high to set the cover charge (entrance fee). O
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a) q(p) = -15p + 300; b) R(p) = -15p² + 300p; c) C(p) = -30p + 1600; d) 1) P(p) = -15p² + 330p - 1600; d) 2) p = $11. To develop the demand equation, we plot the values of the cover charge against the number of guests per night for the given coordinates (9,165) and (10,150). The slope provides the relationship needed to formulate the linear equation relating guests and cover charge. The revenue function follows from multiplying price by guests, while the cost function encompasses overhead and beverage expenses associated with operational costs. The profitability equation emerges from subtracting costs from revenues, allowing us to determine the optimal entrance fee for maximum profit.
5 0
2 months ago
Max has three blue and two red shirts. On each day of the three days,Monday,Tuesday and Wednesday, he selects one shirt at rando
babunello [11817]

Answer:

1) 3/5

2) 40%

3) 60%

Detailed Breakdown:

5 0
3 months ago
A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. A fre
PIT_PIT [12445]
The computed standard deviation is 7588.09.
7 0
2 months ago
Read 2 more answers
Ariah has a hot air balloon. When full, the balloon is a sphere with a radius of 999 meters. She fills it with hot air whose den
PIT_PIT [12445]

Respuesta:

Ariah necesita 2748 kilogramos de aire para llenar el globo.

Explicación paso a paso:

8 0
1 month ago
What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [12517]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
2 months ago
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