Which of the following is true of a CDK molecule if no cyclin is present to bind to it?O CDK is inactive without a cyclin bound

to it. O CDK is larger without a cyclin bound to it.
O CDK becomes unstable and disappears with no cyclin present. O none of the choices

Biology

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Mitosis, the process by which the nucleus of a cell divides into two nuclei, is essential to life because it allows for the form

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Greetings. The right answer is C.

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Convert enzyme concentrations of 2.5%, 5.0%, and 10% to ppt units.

lana [2441]

Answer:

2.5 x 10¹⁰ ppt

5.0 x 10¹⁰ ppt

1.0 x 10¹¹ ppt

Explanation:

The term ppt denotes parts per trillion, meaning how many parts of the enzyme are present in 1 trillion parts. Percentage denotes the number of parts per 100 units. To convert the provided values from percentage to ppt:

$\frac{2.5}{100}=\frac{a}{1,000,000,000,000}\\a=2.5 *10^{10}\ ppt\\\\\frac{5.0}{100}=\frac{b}{1,000,000,000,000}\\b=5.0 *10^{10}\ ppt\\\\\frac{10}{100}=\frac{c}{1,000,000,000,000}\\c=1*10^{11}\ ppt$

The concentrations in ppt are:

2.5 x 10¹⁰ ppt

5.0 x 10¹⁰ ppt

1.0 x 10¹¹ ppt

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Scientists used cells called fibroblasts to study factors that cause nondividing cells in the G0 stage of the cell cycle to reen

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Answer:

Based on observations from the cell groups, the protein p16 seems to have no significant role in preventing fibroblasts from entering the cell cycle. This finding is illustrated in group 7, where the DNA replication rate is nearly as high as that in the 10% serum condition, despite the presence of p16 alone.

In other groups (3 to 6), any additional proteins have always resulted in reduced DNA replication compared to fibroblasts cultured in 10% serum.

Groups 4 to 7 demonstrate a higher likelihood of containing cells that are dividing, as evidenced by their increased DNA replication rates relative to group 1, which has 0% serum. This group, having been cultured for 48 hours without serum (serum-starvation), halts division and transitions into the G0 phase of the cell cycle.

This data is pivotal in identifying which proteins trigger cellular entry into the cycle. For healing post-injury, cellular division and repair are crucial, which can be stimulated by the appropriate protein. Additionally, it will clarify which proteins hinder cell cycle entry.

Note: Figure is attached for reference

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