Five teachers were hired at Oakdale Middle School at the beginning of the 2005 school year. The performance of each teacher was

Answer:

Crearemos una tabla con estos valores según diferentes valores de x.

x                  A                 B                C               D

2              66.66          49.3            52.5           50

4             94.57            71.44           106.3         104  

6             134.14           103.57         160.1          158

8             190.27        150.14          213.9         212

10           269.91           217.64         267.7         266

12           382.85          315.5           321.5          320.

Por lo tanto, la función que mejor representa los datos es:

Opción C.

y=26.9x-1.3

Explicación paso a paso:

Answer:

Possible values for X include;

15, 30, 45, 60, and so on

Step-by-step explanation:

The parameters provided are

Number of chocolates Tanmay possessed = X

Number of chocolates given to Akash = 1/3 × X

Number of chocolates given to Sharad = 1/5 × X

Consequently, since both 3 and 5 divide X,

3 × 5 = 15 is the smallest single factor of X.

Thus, the values of X based on this minimum factor are as follows;

15 × 1 = 15

15 × 2 = 30

15 × 3 = 45

15 × 4 = 60

Therefore, potential values for X form an arithmetic series: a + (n - 1) × d

Where:

a = 15

n = 1, 2, 3, 4,...

d = 15

This results in;

15, 30, 45, 60

Response: 7

Detailed explanation:

A Venn diagram can help visualize this problem.

There are a total of 5 students interested in both French and Latin.

Out of these, 3 students also want to learn Spanish, meaning only 2 students want solely French and Latin.

Moreover, there are 5 students who wish to study only Latin.

This results in 1 student wanting both Latin and Spanish, calculated by 11 - 5 - 3 - 2.

There are 8 students who desire only Spanish, and 4 students who want both Spanish and French.

In the same manner, those wishing to study only French amount to 16 - 4 - 3 - 2 = 7.

Answer:

(a) 4i iterations

(b) "i × n" iterations

Step-by-step explanation:

(a) The provided algorithm segment shows:

for i:= 1 to 4, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

The inner loop executes i times while the outer loop completes 4 cycles.

The inner loop’s total execution when the full algorithm runs is:

= i × 4

= 4i iterations

(b) In the given algorithm segment;

for i:= 1 to n, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

where n denotes a set of positive integers.

= i × n

= "i × n" iterations