A rocket was launched into the air from a podium 6 feet off the ground. The rocket path is represented by the equation h(t)=-16t

The distance from point Y to the flag post measures 38.13 m. Step-by-step explanation: Assuming point Y is located at the intersection of both lines shown. Point X is positioned 34 meters east of point Y. The flagpole at point X is observed at a bearing of N18°W, meaning it creates an angle of 18° to the west from the north at point X. Conversely, at point Y, the flagpole has a bearing of N40°E, which makes a 40° angle towards the east from the north. Considering ∆ AXY as a right triangle, the angle FXY is established. Then, concerning ∆ BYX as another right triangle, the angle FYX is also determined. To find the third angle ∠YFX in triangle FYX, the angle sum property of triangles can be applied: ∠YFX + ∠FYX + ∠FXY = 180° Thus, we have: ∠YFX + 50° + 72° = 180° leading to ∠YFX = 58°. Now we can calculate the distance FY using the sine rule.

Each of the six payments amounts to $41.50

Step-by-step breakdown:

Given,

Total cost of the bike including taxes = $349

Initial payment = $100

Remaining balance = Total cost of bike - Initial payment

Remaining balance = 349 - 100

Remaining balance = $249

She opts to pay in six equal installments, so we divide the total remaining by 6.

Monthly payment =

Monthly payment =

Each of the six payments amounts to $41.50

Keywords: division, subtraction

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The estimated height would be around 3 feet, which would correspond to a level that is approximately at waist height.

A quadratic function in standard form is expressed as
f(x) = ax² + bx + c
with coefficients a, b, and c.

The quadratic function provided is
f(p) = p² - 8p - 5
By relating this to the standard form, where p stands in for x, we find:
a = 1 because the leading coefficient is 1*p²,
b = -8 as the linear part is -8*p,
and c = -5 since the constant is -5.

Based on the choices available, the correct answer is the third one:
a = 1, b = -8, c = -5.

D). 9 ft is indeed the correct answer. The height of the ball at a horizontal distance of 10 feet is 9 ft.