12 days ago

Ethan went to the grocery store and bought bottles of soda and bottles of juice. Each bottle of soda has 45 grams of sugar and e

ach bottle of juice has 35 grams of sugar. Ethan purchased a total of 19 bottles of juice and soda which collectively contain 755 grams of sugar. Determine the number of bottles of soda purchased and the number of bottles of juice purchased.

Mathematics

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While driving from his home to his workplace, Chris has to pass through two traffic lights. The general probability of getting a

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These occurrences are unlikely to take place!

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3 months ago

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CORINA INDRAGESTE FOARTE MULT ANIMALELE IN DAR DE ZIU EI A PRIMIT O CARTE DESPRE LUMEA LOR MINUNATA IN PRIMA ZI EA A CITIT 36 DE

babunello [11817]

The answer I arrived at is related to paging.

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2 months ago

Construct an interval estimate for the given parameter using the given sample statistic and margin of error. For μ1-μ2, using x¯

zzz [12365]

Answer: CI = (0, 8)

Step-by-step explanation: The confidence interval for the difference in means is given as

Lower limit

= (x1 - x2) + margin of error

Upper limit

= (x1 - x2) - margin of error

Where x1 - x2 = 8 and the margin of error = 8

For the lower limit,

= 8 - 8 = 0

For the upper limit

= 8 + 8 = 16

Thus, CI = (0, 8)

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3 months ago

An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40

lawyer [12517]

Response:

0.14 s

Detailed breakdown:

s = -2.7 t² + 40t + 6.5

Set s = 12

12 = -2.7t² + 40t + 6.5 Rearranging yields

-2.7t² + 40t + 6.5 - 12 = 0

-2.7t² + 40t - 5.5 = 0

Utilize the quadratic formula

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = -2.7; b = 40; c = -5.5

$x = \frac{-40\pm\sqrt{40^2 - 4\times (-2.7) \times (-5.5)}} {2(-2.7)}$

$x = \frac{-40\pm\sqrt{1600-59.4}}{-5.4}$

$x = \frac{-40\pm\sqrt{1540.6}}{-5.4}$

$x = \frac{-40\pm 39.25}{-5.4}$

x = 7.41 ± 7.27

x₁ = 0.14; x₂ = 14.68

The graph indicates roots at x₁ = 0.134 and x₂ = 14.68.

The surface of the Moon stands at -12 ft. Thus, the ball will reach a height of 12 ft above the Moon’s surface (crossing the x-axis) at 0.14 s.

The second root indicates when the ball is again 12 ft above the lunar surface as it descends.

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3 months ago