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Assoli18
1 month ago
6

An electrolyte solution has an average current density of 111 ampere per square decimeter \left( \dfrac{\text{A}}{\text{dm}^2}\r

ight)( dm 2 A ​ )left parenthesis, start fraction, A, divided by, d, m, start superscript, 2, end superscript, end fraction, right parenthesis. What is the current density of the solution in \dfrac{\text{A}}{\text{m}^2} m 2 A ​ start fraction, A, divided by, m, start superscript, 2, end superscript, end fraction?
Mathematics
2 answers:
Svet_ta [12.7K]1 month ago
6 0
The solution's average current density is 1 ampere per square decimeter.

We need to convert this value to ampere per square meter.

Since 1 decimeter equals \frac{1}{10} meters,
squaring gives us:

1 square decimeter equals \frac{1}{100} square meters.

Hence, the current density now is 1 \frac{A}{dm^{2} } =1 \frac{A}{ \frac{1}{100} m^{2} } =100Am^{-2}.

Therefore, the current density of the electrolyte solution is 100 amperes per square meter.
PIT_PIT [12.4K]1 month ago
3 0
The correct value is 100; the other individual's calculation is incorrect.:)
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Response:

The equation provided is e=\frac{17}{20}d, where e represents euros and d denotes the equivalent value in U.S. Dollars.


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Step-by-step explanation:


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Step-by-step explanation:

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