By applying Kepler's third law of planetary motion, we understand that the square of the orbital period corresponds to the cube of the semi-major axis. Given that Earth orbits at 1 AU with a 1-year period, we can establish the ratio: P^2 / r^3= 1 (P)^2 = 4^3 <span>P = 4^(3/2) = 8 years </span>