Write a for loop to print each contact in contact_emails. Sample output for the given program:

Answer:

The revised code is as follows:

user_val = int(input())

cond_str = 'non-negative'  

if user_val < 0:

   cond_str = 'negative'  

print(user_val, 'is', cond_str)

Explanation:

This retrieves input for user_val

user_val = int(input())

This sets cond_str to 'non-negative'

cond_str = 'non-negative'

In cases where user_val is below 0

if user_val < 0:

Here cond_str changes to 'negative'

   cond_str = 'negative'  

This displays the intended output

print(user_val, 'is', cond_str)

Answer:

SyntaxError.

Explanation:

https://www.quora.com/In-Python-what-kind-of-error-is-returned-by-the-following-code-e-g-NameError-ValueError-IOError-etc-def-my_func-n1-n2-return-n1-n2-my_func-1-2-3          original source

brainlest plz

Answer: