2. ½ of a group of chickens tried to cross the road. Only ¾ of those chickens made it to the other side. What fraction of the or

The year 1915 marks a population of 15,689. In 1940, it increased to 39,381. The required time to reach this figure is t = 137.9 years. Step-by-step explanation: To answer, we apply an exponential growth formula: A = P (1 + r) t, where P is the original number of individuals, r is the growth rate in decimal, and t is the time in years. Plugging in provided values: A = 6,250 (1 + 0.0375)^t. For the year 1915, as 1915-1890 translates to 25 years: A = 6,250 (1.0375)^25 yields 15,689. For 1940, as 1940-1890 indicates 50 years passed: A = 6,250 (1.0375)^50 results in 39,381. To find when the population hits 1,000,000, substitute A=1,000,000 and solve for t. This leads to 1,000,000/6,250 = (1.0375)^t implying log(160) = t * log(1.0375) results in t being approximately 137.9 years.

Response:

Average = 2000

Step-by-step breakdown:

The numbers provided are:

1,000 2,300 2,600

To calculate the average:

Initially, round each number to the nearest 1000, then determine the average.

Solution:

1000 is already rounded, so it stays the same.

To round to the nearest thousand, check the hundred's digit.

• If the hundred’s digit exceeds 5, the thousand’s digit increases by 1, and the hundred’s digit is set to 0.

• If it’s less than 5, the thousand’s digit remains the same, changing the hundred’s digit to 0.

Thus, 2300 rounds to 2000.

and 2600 rounds to 3000.

Consequently, the numbers for averaging are 1000, 2000, 3000.

The formula for average is as follows:

upon applying the formula:

So, the average after rounding to the nearest 1000 is 2000.