The year 1915 marks a population of 15,689. In 1940, it increased to 39,381. The required time to reach this figure is t = 137.9 years. Step-by-step explanation: To answer, we apply an exponential growth formula: A = P (1 + r) t, where P is the original number of individuals, r is the growth rate in decimal, and t is the time in years. Plugging in provided values: A = 6,250 (1 + 0.0375)^t. For the year 1915, as 1915-1890 translates to 25 years: A = 6,250 (1.0375)^25 yields 15,689. For 1940, as 1940-1890 indicates 50 years passed: A = 6,250 (1.0375)^50 results in 39,381. To find when the population hits 1,000,000, substitute A=1,000,000 and solve for t. This leads to 1,000,000/6,250 = (1.0375)^t implying log(160) = t * log(1.0375) results in t being approximately 137.9 years.
In response to the earlier inquiry, the diagram depicts horizontal lines along with a vertical segment; FB measures 3. If C is defined as 3, then the coordinates for point D would be (-6,-4). I trust this response has clarified your question.
Since m∠abe = 2b, and angle abe consists of angles abf and ebf, we can write:
m∠abe = m∠abf + m∠ebf
To find m∠ebf, rearrange:
m∠ebf = m∠abe - m∠abf
Substitute the given expressions:
m∠ebf = 2b - (7b - 24)
Simplify:
m∠ebf = 2b - 7b + 24
m∠ebf = -5b + 24.
To tackle this issue, we need to clarify what each variable stands for. Here, n indicates the number of pencil packages purchased by Yolanda, while m represents the number of paper pads she buys. We calculate the total cost by multiplying these variables by their individual prices, which helps us determine the expense for both pencil packages and pads of paper.
The expression "1.4n" indicates the overall cost for n pencil packages.
On the other hand, "1.2m" signifies the complete expense for m pads of paper.
As we sum these two expressions, the resulting total reflects the overall expenditure for both items.
The equation "1.4n + 1.2m" summarizes this calculation.
I hope this provides clarity!
Question is Incomplete; Complete question is given below;
A pile of g pounds of gravel exists in a quarry. During the day, 400 pounds of gravel is added to the pile. Two orders of 900 pounds are removed, resulting in the mound holding 1,500 pounds of gravel by day's end. Formulate the equation that accurately illustrates this scenario.
Answer:
The equation that best represents the situation is 
.
Step-by-step explanation:
Given:
Initial gravel amount = '
'.
Currently Given:
Throughout the day, 400 pounds of gravel is added to the pile.
Thus we can conclude;
Gravel amount after addition = 
Also given:
Two orders of 900 pounds are sold and the gravel is taken from the pile.
Hence, two orders of 900 pounds = 
This leads us to state;
Gravel amount post-removal = 
Now Given:
Remaining gravel at the end of day = 1300 pounds.
Therefore, we derive that;
Consequently, the equation that best describes the scenario is .
