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Ilya
9 days ago
8

Match each type of vector reflection with the matrix used to achieve it

Mathematics
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The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
lawyer [12517]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

There are four desktop computers and two laptops.

On a specific day, we will set up 2 of these computers.

To find:

a. What is the probability that both selected computers are laptops?

b. What is the probability that both computers are desktops?

c. What is the probability that at least one computer is a desktop?

d. What is the probability that at least one of each type of computer is included?

Solution:

Using the probability formula for event E:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. The number of successful outcomes for both computers being laptops = _2C_2 = 1

Total possible outcomes = 15

The needed probability is \frac{1}{15}.

b. The successful outcomes for both being desktop computers = _4C_2=6

Total possible outcomes = 15

The required probability is \frac{6}{15} = \frac{2}{5}.

c. For at least one desktop:

Two scenarios exist:

1. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

2. Both are desktops:

Successful outcomes = _4C_2=6

Total successful outcomes = 8 + 6 = 14

The needed probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Successful outcomes = _2C_1\times _4C_1 = 8

Total outcomes = 15

The required probability is \frac{8}{15}.

8 0
3 months ago
Sean took 4 hours to travel from Town A to Town B at an
Leona [12618]

Answer:

Tina's overall average speed for the journey is 56 km/h.

Step-by-step explanation:

Sean's travel time from Town A to Town B is 4 hours.

Sean's average speed is 70 km/h.

Using the motion equation, s = ut + 0.5 at², we can find:
Time, t = 4 hours.

Initial speed, u = 70 km/hr.

Acceleration, a = 0 m/s².

Replacing the variables:

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x 4²

      s = 280 km

The distance from Town A to Town B is 280 km.

Tina's travel time exceeds Sean's by 1 hour.

Tina's time to travel from Town A to Town B is 4 + 1 = 5 hours.

Again applying the motion equation, s = ut + 0.5 at²:

Time, t = 5 hours.

Distance, s = 280 km.

Acceleration, a = 0 m/s².

Putting in values:

      s = ut + 0.5 at²

      280 = u x 5 + 0.5 x 0 x 5²

      u = 56 km/hr.

Tina's overall average speed is thus 56 km/h.

8 0
3 months ago
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