All categories

3 days ago

Sean took 4 hours to travel from Town A to Town B at an

Mathematics

1 answer:

Leona [4.1K]3 days ago

8 0

Answer:

Tina's overall average speed for the journey is 56 km/h.

Step-by-step explanation:

Sean's travel time from Town A to Town B is 4 hours.

Sean's average speed is 70 km/h.

Using the motion equation, s = ut + 0.5 at², we can find:
Time, t = 4 hours.

Initial speed, u = 70 km/hr.

Acceleration, a = 0 m/s².

Replacing the variables:

s = ut + 0.5 at²

s = 70 x 4 + 0.5 x 0 x 4²

s = 280 km

The distance from Town A to Town B is 280 km.

Tina's travel time exceeds Sean's by 1 hour.

Tina's time to travel from Town A to Town B is 4 + 1 = 5 hours.

Again applying the motion equation, s = ut + 0.5 at²:

Time, t = 5 hours.

Distance, s = 280 km.

Acceleration, a = 0 m/s².

Putting in values:

s = ut + 0.5 at²

280 = u x 5 + 0.5 x 0 x 5²

u = 56 km/hr.

Tina's overall average speed is thus 56 km/h.

You might be interested in

The quotient of 9 3/4 and 5/8

AnnZ [3900]

Answer:

15.6

Step-by-step explanation:

$9\frac{3}{4} = \frac{39}{4}$
Insert 39/4: 39/4 ÷ 5/8
39/4 ÷ 5/8 = 39/4 × 8/5
39/4 × 8/5 = 312/20
$\frac{312}{20} = 15.6$

I hope this information is helpful!

4 0

3 days ago

Read 2 more answers

Mary wrote a book of 1536 pages. She numbered all pages by hand. How many times did she write the digit 6?

lawyer [4039]

Response:

404 instances

Detailed breakdown:

8 0

8 days ago

If BCD ~ GEF, find BD

PIT_PIT [3949]

Response:

BD equals 19

Detailed breakdown:

4 0

4 days ago

LMN is a straight angle. Find m LMP and m NMP

PIT_PIT [3949]

Answer:

(-16x + 13)° + (-20x + 23)° = 180° (ángulo recto)

-16x° + 13° - 20x° + 23° = 180°

-36x° + 36° = 180°

-36x° = 180° - 36°

-36x° = 144°

-x° = 144°/(-36)

x° = 36°

Espero que puedas conocer esta respuesta

3 0

9 days ago

When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t

zzz [4035]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

$\boxed{u \ or \ v_i = initial \ velocity}$

$\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}$

$\boxed{a = acceleration \ (constant)}$

$\boxed{d = distance \ travelled}$

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

$\boxed{ \ v^2 = u^2 + 2ad \ }$

a = acceleration (m/s²)
u = initial speed = 0 m/s
v = takeoff velocity = 1.0 m/s
d = displacement = 0.50 mm

First, convert 0.50 mm to meters: $\boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}$

Solution steps:

Rearrange the formula to isolate acceleration (a).

$\boxed{ \ v^2 = u^2 + 2ad \ }$

$\boxed{ \ v^2 - u^2 = 2ad \ }$

$\boxed{ \ 2ad = v^2 - u^2 \ }$

$\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }$

Insert the given values into the rearranged equation.

$\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }$

$\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }$

$\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }$

$\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }$

This yields the flea's acceleration as 1,000 m/s².

Additional resources

Scientific notation: brainly.com/question/7263463
Determining substance mass: brainly.com/question/4053884
Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

5 0

14 days ago

Read 2 more answers