Write a function solution that returns an arbitrary integer which is greater than n.

Answer:

public static int greaterThanInt(int n) {

       return n + 10;

   }

Explanation:

This Java method is quite straightforward. It takes an integer n as an argument and will return n+10 because the requirement is to provide an integer that exceeds n; adding any integer to n will fulfill that condition.

A complete Java program that calls this method is presented below:

import java.util.Scanner;

public class ANot {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Please enter an integer");

       int n = in.nextInt();

       int greaterInt = greaterThanInt(n);

       System.out.println("You entered " + n + ", " + greaterInt + " is larger than it");

   }

   public static int greaterThanInt(int n) {

       return n + 10;

   }

}