Q) Select the two obstacles for data parsing

The answer is back up

Answer:

Clarification:

The most effective recommendation for the agency would be to ensure they fully grasp the overall ownership costs of the server. This encompasses not only the server itself but also various factors including necessary software, an IT server manager, facility expenses, security investments, and backup options. Although these are key costs they will face, there may be additional unexpected expenses. Consequently, the best approach is to supply them with comprehensive information for making an informed decision.

// Below is Java code. // Package import import java.util.*; // class definition class Main { // class main method public static void main (String[] args) throws java.lang.Exception { try{ // variables final int CENTS_PER_POUND = 25; final int FLAT_FEE_CENTS = 75; // Creating Scanner object for input Scanner sr=new Scanner(System.in); System.out.print("Enter the shipping weight:"); // input reading int shipWeightPounds=sr.nextInt(); // cost calculation int shipCostCents = (shipWeightPounds * CENTS_PER_POUND) + FLAT_FEE_CENTS; // output Weight System.out.println("shipping Weight: " + shipWeightPounds); // output flat fee System.out.println("flat fee of shipping in cents: " + FLAT_FEE_CENTS); // output cents per pound System.out.println("Cents/pound for shipping: " + CENTS_PER_POUND); // output shipping cost System.out.println("total cost of shipping in cents: " + shipCostCents); catch(Exception ex){ return;} } } // Explanation: Define two constants "CENTS_PER_POUND=25" and "FLAT_FEE_CENTS=75". Use a Scanner object to capture user input for weight. Calculate the shipping cost by multiplying the weight with cents per pound and adding the flat fee. Then, display each value.

int currentNumber,previousNumber = -1, countDuplicates = 0;

do {

cin >> currentNumber;

if ( previousNumber == -1) {

previousNumber = currentNumber;

}else {

if ( previousNumber == currentNumber )

countDuplicates++;

else

previousNumber = currentNumber;

}

} while(currentNumber > 0 );

cout << countDuplicates;

Response:

The code is provided below

Clarification:

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.nio.charset.StandardCharsets;

public class Main {

  /**

  *

  * Process each line of input.

  *

  */

  public static void main(String[] args) throws IOException {

      InputStreamReader reader = new InputStreamReader(System.in, StandardCharsets.UTF_8);

      BufferedReader in = new BufferedReader(reader);

      String line;

      while ((line = in.readLine())!= null) {

          String[] splittedInput = line.split(";");

          String pattern = splittedInput[0];

          String blobs = splittedInput[1];

          Main.doSomething(pattern, blobs);

      }

  }

  public static void doSomething(String pattern, String blobs) {

      // Implement your code here. You can create more methods or classes if needed

      int total = 0;

      String arrblobs[] = blobs.split("\\|");

      for (int i = 0; i < arrblobs.length; ++i) {

          int count = 0, index = 0;

          for (;;) {

              int position = arrblobs[i].indexOf(pattern, index);

              if (position < 0)

                  break;

              count++;

              index = position + 1;

          }

          System.out.print(count + "|");

         

          total += count;

      }

      System.out.println(total);

  }

}