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blagie
6 days ago
11

The weights of tennis balls are normally distributed, with the mean being 5.15 ounces and the standard deviation being 0.10. wha

t percentage of the balls weigh within one standard deviation of the mean? 50% 68% 95% 99.7%
Mathematics
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1. A manufacturer claims that the mean lifetime of its fluorescent bulbs is 1500 hours. A homeowner selects 40 bulbs and finds t
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(1) The sample mean stands at 1480 hours while the population standard deviation is 80 hours.(2) The null hypothesis posits that the average lifespan of fluorescent bulbs is 1500 hours.(3) The critical value is 1.645.(4) The test statistic is D, -1.58.(5) The conclusion is B, we reject H0.(6) Thus, the conclusion indicates A, there isn't sufficient evidence to substantiate the claim that the average lifespan of its fluorescent bulbs is 1500 hours.
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2 months ago
Mary wrote a book of 1536 pages. She numbered all pages by hand. How many times did she write the digit 6?
lawyer [12517]

Response:

404 instances

Detailed breakdown:

8 0
3 months ago
The half-life of carbon-14, 14C, is approximately 5,730 years. A bone fragment is estimated to have originally contained 6 milli
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6 0
2 months ago
Jeremy looked at this table of prices and said the cost for renting a bike is $7.00 per hour.
Leona [12618]

Answer:

Hours

Step-by-step explanation:

This is an incorrect figure.

5 0
3 months ago
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One similar figure has an area that is nine times the area of another. The larger figure must have dimensions that are times the
Svet_ta [12734]
T<span>he area of a figure signifies the measure of space within a two-dimensional shape, typically expressed as square units based on the figure's dimensions.

For instance, with a shape having dimensions of k, its area can be given by k^2.
</span>
<span>Consider that one similar figure possesses an area nine times that of another.

As these figures are similar, their areas correspond to the proportionality of their dimensions.

Let the smaller shape's dimensions be k, while the larger is p times the dimensions of the smaller shape. The smaller shape's area is k^2 and the larger shape's area is (pk)^2.

Now, knowing the larger figure's area is nine times the area of the smaller figure, we have:
\frac{(pk)^2}{k^2} = \frac{9}{1} \\ \\ \frac{p^2k^2}{k^2} =9 \\ \\ p^2=9 \\ \\ p= \sqrt{9} \\ \\ p=3
</span>
Thus, the dimensions of the larger figure must be 3 times those of the smaller figure.
3 0
2 months ago
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