The electric force between two objects is expressed as being proportional to the product of their charges and inversely proportional to the square of the distance separating them. In this instance, the distance between the first two charges is 19 cm. We formulate the equation k q1 q3/ (x)^2 = k q2 q3/ (19-x)^2, where x denotes the separation between q1 and q3. The charge q3 cancels out, and q2 is used in absolute terms. The resulting value of x is 5.79 cm.
Response:
C. vx
F. ax
G. ay
Clarification:
The projectile follows a curved trajectory toward the ground, causing changes in x and y positions.
Since there is no external force acting in the x-direction, the acceleration in x remains at zero. Consequently, ax and vx remain unchanged.
The projectile is subject to the force of gravity, directed downwards, leading to an increase in its velocity due to the rise in its y-component.
Meanwhile, the y-component of acceleration remains constant due to gravitational acceleration.
For this issue, the answer is clarified as the system takes in energy (+). The surroundings contribute 84 KJ of work. Whenever a system is receiving work from its surroundings, the value will be positive. Therefore, it sums to 12.4 KJ + 4.2 = 16.6 KJ.
