Answer:
The particle's kinetic energy will equal 12U₀.
Explanation:
Given that,
A particle is fired from point B with an initial speed and arrives at point A with U₀ joules of kinetic energy gained.
The consistent force acting is 12F.
As per the problem,
The kinetic energy is
....(I)
Constant force remains at 12F.
A resistive force field now exists,
With the resistive force defined as,
As the particle travels from point B to point A,
We need to find the kinetic energy
Using the kinetic energy formula
Substituting values for 
Then, from equation (I)
Consequently, the particle’s kinetic energy will amount to 12U₀.
Answer:
Explanation:
When calculating Hall voltage, it is crucial to have the current, magnetic field strength, length, area, and number of charge carriers available. The Hall voltage can be expressed using the equation:
Where:
i= the current
B= the magnetic field strength
L = the length
n = the number of charge carriers
e= charge of an electron
We need to replace values and solve for n:
As a result, the charge carrier density is
Response:
0.9 cm
Clarification:
The following illustrates the calculation of the combined rod's length increase:
As established
Length increase = expansion of aluminum rod + expansion of steel rod
= 0.9 cm
We simply summed the expansions of both the aluminum and steel rods to determine the overall increase in the joined rod's length, which must be factored in
Answer:
Explanation:
a) La fuerza neta que actúa sobre la caja en la dirección vertical es:
Fnet=Fg−f−Fp *sin45 °
aquí Fg representa la fuerza gravitacional, f es la fuerza de fricción, y Fp es la fuerza de empuje.
Fnet=ma
ma=Fg−f−Fp *sin45 °
a=
=0.24 m/s²
Vf =Vi +at
=0.48+0.24*2
Vf=2.98 m/s
b)
Fnet=Fg−f−Fp *sin45 °
=Fg−0.516Fp−Fp *sin45 °
=30-1.273Fp
Fnet=0 (Ya que la velocidad es constante)
Fp=30/1.273
=23.56 N
Answer:
R=V/I=6/2=3 ohm
time = 5 minutes = 5*60=300 seconds
I=2 A
Energy = I²Rt=(2)²*3*300=4*900=3600 J
