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Dimas
8 days ago
11

Charlie has the utility function u(xa, xb) =xaxb.his indifference curve passing through 32 applesand 8 bananas will also pass th

rough the point where he consumes 4 apples and
Mathematics
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A house cleaning service claims that it can clean a four bedroom house in less than 2 hours. A sample of n = 16 houses is taken
Zina [12379]

Response:

Option B is correct

Step-by-step breakdown:

H_0: x bar =2\\H_a: x bar

(One-tailed test at a significance level of 5%)

n = 16 and x̄ = 1.97

s = 0.1

Standard error of the mean = \frac{s}{\sqrt{n} } \\=0.025

Difference in means = 1.97-2 =-0.03

t statistic = Difference in means/se = -1.2

degrees of freedom = 16 - 1 = 15

p-value = 0.124375

(B) do not reject the null hypothesis since the test statistic (-1.2) is > the critical value (-1.7531).

3 0
2 months ago
Express 9 ten thousandths in Scientific notation
zzz [12365]
<span>9 ten thousandths equals 0.0009, which can be expressed as 9 × 10 to the power of -4</span>
5 0
4 months ago
Read 2 more answers
For the given position vectors r(t) compute the unit tangent vector T(t) for the given value of t .
Svet_ta [12734]

Answer:

a) T(t) = \frac{}{5}=

T(4) =

b) T(t) = \frac{}{8\sqrt{37}}

T(4) =

c) T(t) = \frac{}{2425825977}

T(4) = \frac{1}{2425825977}

Step-by-step explanation:

The tangent vector is determined as follows:

T(t) = \frac{r'(t)}{|r'(t)|}

Part a

The given function for this instance is:

r(t) =

The derivative is calculated as:

r'(t) =

The magnitude of the derivative is determined by:

|r'(t)| = \sqrt{25 sin^2(5t) +25 cos^2 (5t)}= 5\sqrt{cos^2 (5t) + sin^2 (5t)} =5

Thus, the tangent vector is found to be:

T(t) = \frac{}{5}=

Finally, for t=4 we find:

T(4) =

Part b

In this case, we have the stated function:

r(t) =

The derivative can be expressed as:

r'(t) =

The magnitude for the derivative is calculated as:

|r'(t)| = \sqrt{4t^2 +9t^4}= t\sqrt{4 + 9t^2}

|r'(4)| = \sqrt{4(4)^2 +9(4)^4}= 4\sqrt{4 + 9(4)^2} = 4\sqrt{148}= 8\sqrt{37}

Thus, the tangent vector in this case is:

T(t) = \frac{}{8\sqrt{37}}

Finally, when t=4 we find:

T(4) =

Part c

Here, we have the corresponding function stated:

r(t) =

The derivative is stated as:

r'(t) =

The magnitude for the derived value is calculated as:

|r'(t)| = \sqrt{25e^{10t} +16e^{-8t} +1}

|r'(t)| = \sqrt{25e^{10*4} +16e^{-8*4} +1} =2425825977

Therefore, we conclude the tangent vector here:

T(t) = \frac{}{2425825977}

And for the case when t=4, we get:

T(4) = \frac{1}{2425825977}

5 0
3 months ago
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