The sum of 48 and itself its half and half of the hal is added to 18​

Response:

24.2 (rounded to the nearest tenth)

Detailed breakdown:

The data type involved is ungrouped

standard deviation =√ [∑ (x-μ)² / n]

average (μ)=∑x/n

           =

          =33.3

For the values 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84, the x-μ results will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

Calculating (x-μ)² gives: 800.89, 800.89, 745.29, 453.69, 53.29, 13.69, 246.49, 313.29, 515.29, 515.29, 2570.49

Then, ∑ (x-μ)² results in = 7028.59

Thus, standard deviation = √(7028.59 / 12)

                      =24.2

     

In order to determine this probability, we calculate using this difference: To obtain these probabilities, it’s possible to utilize normal standard distribution tables, a calculator, or software like Excel. The accompanying figure displays the results achieved. Here’s a detailed breakdown of the steps: Relevant concepts include the normal distribution, which describes a probability distribution that is symmetric regarding the mean, demonstrating that occurrences close to the mean are more likely than those farther away. The Z-score represents a statistical measure illustrating how far a value is from the average of a set, expressed in standard deviations. For our analysis, let X denote the random variable representing weights in a population, with its distribution characterized by: We’re specifically interested in this probability. The most effective approach to address this issue is through the standard normal distribution and the Z-score calculation, expressed as: Applying this formula to our probability provides the following: This allows us to calculate this probability with the provided difference: We use standard distribution tables, a calculator, or Excel for determining these probabilities. The graph illustrates the resulting outcome.

Here’s a counterexample: consider

Select the subsets in the following manner:

It's accurate that and and that , but

Answer:

C. 181.7 miles

1) For the expected number in 200 restaurants where exactly 8 customers use the drive-through, it is 20.66. Similarly, for exactly 9 customers, the expected count is 13.76. To compute these expectations, we utilize the Poisson distribution which defines the success probability X, considering a certain operational rate for the drive-through services during specified times.