Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
Answer:
Refer to the detailed explanation below
Step-by-step explanation:
* Let’s organize the procedure to bisect angle ABC
- Angle ABC has vertex at point B and rays BA and BC
# Step 1:
- Center the compass at point B and draw an arc that crosses rays BA and BC ⇒ fifth step
# Step 2:
- Mark point D where the arc intersects ray BA and point E where it meets ray BC ⇒ third step
# Step 3:
- With the compass on point D, create an arc inside the angle ⇒ sixth step
# Step 4:
- Using the same compass width, set it on point E and draw an arc inside the angle ⇒ second step
# Step 5:
- Let point F be the intersection of the arcs from points D and E ⇒ fourth step
# Step 6:
- Draw a ray from point B through point F ⇒ first step
* This ray divides angle ABC into two equal parts
Answer with explanation:
Total number of children = x
Total chocolates shared = y
In total, the chocolates distributed to the children equals 5 times the number of children, or 5 x.
Chocolates received by adults equal 20.
Let the number of adults be z.
Expressing this situation as an equation:
y = 5 x + 20 z
⇒Number of adults = z
Answer:
A), B), and C) are clarified below.
Step-by-step explanation:
The inquiry involves using binary digits, employing probabilities that are equal for both conditions, by applying a random test pattern, where the formula is derived from p = q.
Simplifying gives us
P[k] = nCk / 2^n
A. Probability of all bits being 1s
16c16/2^16 = 1/65536
B. Probability of all bits being 0s
16c0/2^16 = 1/65536
C. The probability of having exactly 8 bits as 1s and the other 8 as 0s
16c8/2^16 = 12870/65536 => 0.1963 ≈ 19.63%
