A method countDigits(int num) of class Digits returns the remainder when the input argument num(num > 0) is divided by the nu

Answer:

#include <iostream>

using namespace std;

class Digits

{

   public:

   int num;

   int read()       //method to read num from user

   {

       cout<<"Enter number(>0)\n";

       cin>>num;

       return num;

   }

   int digit_count(int num)  //method to count number of digits of num

   {

       int count=0;

       while(num>0)    //loop till num>0

       {

           num/=10;

           count++;   //counter which counts number of digits

       }

       return count;

   }

   int countDigits(int num)   //method to return remainder

   {

       int c=digit_count(num); //calls method inside method

       return num%c;  

   }

};

int main()

{

   Digits d;    //object of class Digits is created

   int number=d.read();   //num is read from user

   cout<<"\nRemainder is: "<<d.countDigits(number);  //used to find remainder

   return 0;

}

Output:

Enter number(>0)

343

Remainder is: 1

Explanation:

The program has a logical error that needs rectification. A correctly structured program calculates the remainder when a number is divided by the count of its digits. A class named Digits is created, consisting of the public variable 'num' and methods for reading input, counting digits, and calculating the remainder.

• read() - This function asks the user to enter the value for 'num' and returns it.
• digit_count() - This function accepts an integer and counts how many digits it has, incrementing a counter until 'num' is less than or equal to 0. It ultimately returns the digit count.
• countDigits() - This function takes an integer and delivers the remainder from dividing that number by its digit count. The digit count is computed using the 'digit_count()' method.

Finally, in the main function, a Digits object is instantiated, and its methods are utilized to produce an output.