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Butoxors
1 month ago
10

A method countDigits(int num) of class Digits returns the remainder when the input argument num(num > 0) is divided by the nu

mber of digits in num. The function compiles successfully but fails to return the desired result due to logical errors. Your task is to debug the program to pass all the test cases.
Computers and Technology
1 answer:
ivann1987 [930]1 month ago
7 0

Answer:

#include <iostream>

using namespace std;

class Digits

{

   public:

   int num;

   int read()       //method to read num from user

   {

       cout<<"Enter number(>0)\n";

       cin>>num;

       return num;

   }

   int digit_count(int num)  //method to count number of digits of num

   {

       int count=0;

       while(num>0)    //loop till num>0

       {

           num/=10;

           count++;   //counter which counts number of digits

       }

       return count;

   }

   int countDigits(int num)   //method to return remainder

   {

       int c=digit_count(num); //calls method inside method

       return num%c;  

   }

};

int main()

{

   Digits d;    //object of class Digits is created

   int number=d.read();   //num is read from user

   cout<<"\nRemainder is: "<<d.countDigits(number);  //used to find remainder

   return 0;

}

Output:

Enter number(>0)

343

Remainder is: 1

Explanation:

The program has a logical error that needs rectification. A correctly structured program calculates the remainder when a number is divided by the count of its digits. A class named Digits is created, consisting of the public variable 'num' and methods for reading input, counting digits, and calculating the remainder.

  • read() - This function asks the user to enter the value for 'num' and returns it.
  • digit_count() - This function accepts an integer and counts how many digits it has, incrementing a counter until 'num' is less than or equal to 0. It ultimately returns the digit count.
  • countDigits() - This function takes an integer and delivers the remainder from dividing that number by its digit count. The digit count is computed using the 'digit_count()' method.

Finally, in the main function, a Digits object is instantiated, and its methods are utilized to produce an output.

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Response:

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Reasoning:

Let's denote the size of a large server as L and the size of a smaller server as S.

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Answer:

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Nested conditionals occur when if or else if statements are placed within another condition. For instance:

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}  }

Excessive nested conditionals can complicate the program, rendering it hard to read or comprehend, particularly if there's improper indentation. Debugging also becomes challenging when there are numerous nested statements.

Thus, several strategies can be adopted to eliminate nested conditionals, such as utilizing a switch statement.

For instance, I’ll present an example of the strategies discussed earlier:

Logical Expressions Usage:

A method to avoid nested conditionals is by employing logical expressions with logical operators like the AND operator. The previous nested conditionals can be reframed as:

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This can be further simplified to one condition as:

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}

else

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Now, consider a simple instance dealing with whether to attend school based on certain conditions.

if (temperature< 40)

{

   if (busArrived=="yes")

   {

       if (!sick)

       {

           if (homework=="done")

           {

               printf("Go to school.");

           }

       }                    

   }

}

Here, nested conditionals are evident. This can be restructured into a solitary conditional using the AND logical operator.

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{    cout<<"Eligible for promotion."; }

The alternate method is utilizing an interface. For example, you can

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//declare a method common to all sub classes

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class Triangle extends Shape{

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  }

}

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Now, you can readily create Rectangle or Triangle instances and invoke area() for any of those objects, resulting in execution of the appropriate version accordingly.

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Answer:

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Answer:

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