Answer:
Explanation:
The position of the charge q₁ is established at (0,0)
Meanwhile, the charge q₂ is located at (x₁,0)
Thus, the electric potential energy between these two charges is determined by:
Now, the location of charge q₂ shifts from (x₁,0) to (x₂,y₂). The updated electric potential energy between the charges can be represented as:
According to the work-energy theorem, the alteration in potential energy corresponds to the work performed. This is expressed mathematically as:
Consequently, the work done by the electrostatic force on the moving charge is 
. Therefore, this concludes the solution.
<span>You are presented with a circuit that includes a 6.0-v battery, a 4.0-ohm resistor, a 0.60 microfarad capacitor, an ammeter, and a switch all connected in series. Your task is to determine the current reading once the switch is closed. Ohm's law should be used, which states V = IR where V signifies voltage, I indicates current, and R represents resistance.</span>
V = IR
I = V/R
I = 6 volts / 4 ohms
I = 1.5A
Upon closing the switch, the cathode side plate starts accumulating electrons if it was previously empty. As this process continues, the current diminishes. Eventually, when the capacitor reaches its maximum electron retention, the current will cease. An increased capacitance means a greater capacity for electron storage.
