Response:
3.5 N
Reasoning:
Taking the 0 cm position as the pivot point, to achieve balance, the total moment calculated around this point must equal zero. We will analyze the moment generated at each point, moving from 0 to 100 cm:
- Tension from the string at the 0 cm mark is 0, since the moment arm is nonexistent.
- A 2 N weight at the 10 cm point creates a moment of 20 Ncm moving clockwise.
- Another 2 N weight at the 50 cm position produces a moment of 100 Ncm also clockwise.
- The weight of the 1 N stick located at its center of mass (50 cm) has a moment of 50 Ncm, clockwise.
- A 3 N weight at the 60 cm position generates a moment of 180 Ncm, clockwise.
- The tension T (N) from the string at the 100 cm end contributes a moment of 100T Ncm, moving counter-clockwise.
Total clockwise moments = 20 + 100 + 50 + 180 = 350 Ncm.
Total counter-clockwise moment = 100T.
To achieve balance, we set 100 T = 350, leading to T = 350 / 100 = 3.5 N.
