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Levart
3 months ago
15

An employee receives a pay increase from $35,000 per year to $37,500 per year. Calculate the percent increase. Round to the near

est tenth of a percent.
Mathematics
2 answers:
Leona [12.6K]3 months ago
8 0

Answer:

The employee's salary has increased by 7.14%.

Step-by-step explanation:

Provided:

The employee's original salary = $35,000 annually

The new salary of the employee = $37,500 annually

Let X denote the salary percentage increase.

Thus, X = \frac{increase salary - initial salary}{initial salary} × 100

Or, X = \frac{$37,500 - $35,000}{$35,000} × 100

Or, X = \frac{$2,500}{$35,000} × 100

Therefore, X = 0.0714 × 100 = 7.14%

Thus, the percentage increase in the employee's salary is 7.14%.

Leona [12.6K]3 months ago
7 0

Answer:

The salary increase percentage is 7.14%.

Step-by-step explanation:

An employee's pay rose from $35,000 to $37,500 per year. Hence, the initial pay was $35,000 per year.

The new pay the employee gets is $37,500.

Salary increase =

New pay per year - Previous pay per year, leading to:

Salary increase = 37,500 - 35,000

= $2500

The percent increase = Salary increase / Previous pay per year × 100, resulting in:

2500/35000 × 100

7.14%

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