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tamaranim1
13 days ago
14

The yearly cost in dollars, y, for a member at a video game arcade based on total game tokens purchased, x, is y =y equals Start

Fraction 1 Over 10 EndFraction x plus 60.X + 60. A nonmember pays $0.20 per game token, but no yearly fee. Which equation represents the yearly cost for a nonmember at the same video game arcade based on the total number of game tokens purchased in a year?
Mathematics
2 answers:
Leona [4.1K]13 days ago
6 0

Response:

y = \frac{1}{5}x

Step-by-step explanation:

Given data:

Annual cost for members: y = \frac{1}{10}x + 6

Required:

Calculate the yearly expense for non-members

From the context, we infer that:

A non-member pays $0.20 per game;

Annual cost can be determined using the formula;

y = Amount * Number of Games

Where:

Amount = $0.2, Number of Games = x

y = 0.20 * x

Convert 0.2 to a fraction:

y = \frac{2}{10} * x

Divide the numerator and denominator by 2:

y = \frac{1}{5} * x

y = \frac{1}{5}x

Therefore, the yearly expense for non-members is

y = \frac{1}{5}x

Svet_ta [4.3K]13 days ago
4 0

Response:

y = y equals 1 Over 5 x. x

Detailed explanation:

So c

please rate me brainliest i need 5!!!!!!

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Answer:

4

Step-by-step explanation:

Each sandwich costs 6 dollars, while chips sell for 3 dollars. She purchased 5 sandwiches at 6 dollars each, amounting to 30 dollars (5*6=30). This leaves her with 12 dollars to use since her total expenditure was 42 dollars. Given that chips are 3 dollars each, with 12 dollars left, 4 bags could be bought (4 * 3 = 12).

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3 days ago
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Keitaro walks at a pace of 3 miles per hour and runs at a pace of 6 miles per hour. Each month, he wants to complete at least 36
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Answer:

Option 1 is valid, which entails 2 hours of walking and 12 hours of running.

Step-by-step explanation:

The equations provided are:

3w + 6r ≥ 36

3w + 6r ≤ 90

We'll assess which options comply with these equations.

1) 2 hours walking; 12 hours running

w = 2 and r = 12

3w + 6r ≥ 36

3(2) + 6(12) ≥ 36

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78 ≥ 36

3w + 6r ≤ 90

3(2) + 6(12) ≤ 90

6+72 ≤ 90

78 ≤ 90

Both equations are satisfied. Option 1 is valid.

2) 4 hours walking; 3 hours running

w = 4 and r = 3

3w + 6r ≥ 36

3(4) + 6(3) ≥ 36

12+18 ≥ 36

30 ≥ 36 (this does not hold since 30 < 36)

3w + 6r ≤ 90

3(4) + 6(3) ≤ 90

12+18 ≤ 90

30 ≤ 90

Thus, Option 2 is invalid.

3) 9 hours running; 12 hours walking

w = 9 and r = 12

3w + 6r ≥ 36

3(9) + 6(12) ≥ 36

27+72 ≥ 36

99 ≥ 36

3w + 6r ≤ 90

3(9) + 6(12) ≤ 90

27+72 ≤ 90

99 ≤ 90 (this does not hold since 99 > 90)

Option 3 is invalid.

4) 12 hours walking; 10 hours running

w = 12 and r = 10

3w + 6r ≥ 36

3(12) + 6(10) ≥ 36

36+60 ≥ 36

96 ≥ 36

3w + 6r ≤ 90

3(12) + 6(10) ≤ 90

36 + 60 ≤ 90

96 ≤ 90 (this does not hold since 96 > 90)

So, Option 4 is invalid.

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555 grams of wool were needed to knit a sweater, a hat, and a scarf. The hat required 5 times less wool than the sweater and 5 g
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Answer:

The amount of wool required for a sweater was 400 grams.

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A scarf required 75 grams of wool.

Step-by-step explanation:

Let

x ------> grams of wool necessary for a sweater

y -----> grams of wool necessary for a hat

z -----> grams of wool necessary for a scarf

From the information given

x+y+z=555 -----> equation A

y=x/5 ----> x=5y -----> equation B

y=z+5 ---> z=y-5 ----> equation C

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