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dusya
2 days ago
13

Find the area of trapezoid $DUCK$ shown below. [asy] unitsize(2mm); defaultpen(linewidth(.7pt)+fontsize(10pt)); pair D=(0,0), U=

(5,12), C=(20,12), K=(36,0), F=(5,0); draw(D--U--C--K--cycle); draw(U--F,linetype("8 4")); draw(rightanglemark(U,F,K,25)); label("$D$",D,SW); label("$U$",U,N); label("$C$",C,NE); label("$K$",K,SE); label("5",midpoint(D--F),S); label("13",midpoint(D--U),NW); label("15",midpoint(U--C),N); label("20",midpoint(C--K),NE); [/asy]
Mathematics
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Ben participated in a race. During the first half of the race, he walked 3 miles and ran at a rate of 5 miles per hour for x hou
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Y = 5x + 3
y = 5.5x + 2
0.5x = 1
x = 2
y = 13
I trust this information will assist you. c:
3 0
2 months ago
Read 2 more answers
Tom started an entertainment company. The net value of the company (in thousands of dollars) ttt months after its creation is mo
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Step-by-step explanation: The entertainment company’s net value after t months can be expressed by the equation; v(t) = 4t² - 24t - 28. To factor this expression, we need to simplify the equation: v(t) = 4t² - 24t - 28, dividing everything by 4 yields: v(t) = t² - 6t - 7, v(t) = t² - 7t + t - 7, v(t) = t(t-7) + 1(t-7), v(t) = (t+1)(t-7). Thus, the function in factored form is v(t) = (t+1)(t-7). To find when the company hits its lowest value, substitute v(t) = 0 into the factored expression: v(t) = (t+1)(t-7). Setting equal to zero provides: (t+1)(t-7) = 0, leading to t + 1 = 0 and t - 7 = 0; thus, t = -1 and t = 7. Since time cannot be negative, therefore, t equals 7 months. This indicates that after 7 months, the company will reach its minimal net value.
8 0
2 months ago
The weights of certain machine components are normally distributed with a mean of 8.01 g and a standard deviation of 0.06 g. Fin
PIT_PIT [12445]

Answer:

Option D) 7.90 g and 8.12 g

Step-by-step explanation:

The details provided in the question are:

Mean, μ = 8.01 g

Standard Deviation, σ = 0.06 g

The weights are distributed in a bell-shaped normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We need to determine the value of x for which the probability is 0.03.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 8.01}{0.06})=0.03  

= 1 -P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.03  

=P( z \leq \displaystyle\frac{x - 8.01}{0.06})=0.97  

Using the standard normal z table, we find that,

\displaystyle\frac{x - 8.01}{0.06} = 1.881\\\\x = 8.12  

Thus, the value of 8.17 g separates the upper 3% of the weights.

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 8.01}{0.06})=0.03  

From the standard normal z table, we derive,

\displaystyle\frac{x - 8.01}{0.06} = -1.881\\\\x = 7.90  

Consequently, 7.90 separates the lower 3% of the weights.

<ptherefore the="" accurate="" answer="" is="">

Option D) 7.90 g and 8.12 g

</ptherefore>
7 0
3 months ago
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