Answer:
Answer and Explanation:
We have:
Population mean,
μ
=
3
,
000
hours
Population standard deviation,
σ
=
696
hours
Sample size,
n
=
36
1) The standard deviation for the sampling distribution:
σ
¯
x
=
σ
√
n
=
696
√
36
=
116
2) By the central limit theorem, the sampling distribution's expected value matches the population mean.
Thus:
The expected value of the sampling distribution equals the population mean,
μ
¯
x
=
μ
=
3
,
000
The standard deviation of the sampling distribution,
σ
¯
x
=
116
The sampling distribution of
¯
x
is roughly normal due to a sample size greater than
30
.
3) The likelihood that the average lifespan of the sample falls between
2670.56
and
2809.76
hours:
P
(
2670.56
<
x
<
2809.76
)
=
P
(
2670.56
−
3000
116
<
z
<
2809.76
−
3000
116
)
=
P
(
−
2.84
<
z
<
−
1.64
)
=
P
(
z
<
−
1.64
)
−
P
(
z
<
−
2.84
)
=
0.0482
In Excel: =NORMSDIST(-1.64)-NORMSDIST(-2.84)
4) The probability of the average life in the sample exceeding
3219.24
hours:
P
(
x
>
3219.24
)
=
P
(
z
>
3219.24
−
3000
116
)
=
P
(
z
>
1.89
)
=
0.0294
In Excel: =NORMSDIST(-1.89)
5) The likelihood that the sample's average life is lower than
3180.96
hours:
P
(
x
<
3180.96
)
=
P
(
z
<
3180.96
−
3000
116
)
=
P
(
z
<
1.56
)
=
0.9406
Answer:
Michael purchases 60 kg of dark chocolate alongside 40 kg of milk chocolate.
Step-by-step explanation:
Let d signify the kilograms of dark chocolate bought by Michael and m signify the kilograms of milk chocolate he acquires.
He must acquire a total of 100 kg of chocolate, thus
With dark chocolate priced at $12 per kg, the cost for d kg would be $12d. The price of milk chocolate is $10 per kg, indicating the cost for m kg is $10m. Michael intends to spend $1,120 on the chocolate, therefore
Taking the first equation
By inserting this into the second equation:
Michael ends up buying 60 kg of dark chocolate and 40 kg of milk chocolate.
The solution for y is y = \frac{a}{3(3 + x)}
Answer:
A Type II error occurs when the null hypothesis is not rejected, even when the alternative hypothesis is actually valid.
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The implication is that the new method may be dismissed or altered despite it being a real enhancement.
Step-by-step explanation:
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