Answer:
89
Step-by-step explanation:
Given that
2 O, 2 T and 1 M
Now based on this, the following arrangements exist
1
Three arrangements i.e. {M,T,O}
2
XX or XY
XX in 2C1 = two arrangements i.e. {OO or TT}
XY in 3C2 × 2! = six arrangements
3
XXY or XYZ
XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve arrangements
XYZ in 3C3 × 3! = six arrangements
4
XXYY or XXYZ
XXYY = 4! ÷ (2! × 2!) = six arrangements
XXYZ in 2C1 × 4! ÷ 2! = twenty four arrangements
5
= 5! ÷ (2! ×2!)
= 120 ÷ 4
= 30
Thus, the overall total is
= 3 + (2 +6)+ (12 +6) + (6 +24) + 30
= 89
