Answer:
a
The value at a point inside is Zero
b
The electric field is
Explanation:
We know from the problem that
The charge magnitude is
The radius of the spherical ball is
According to Gauss’s law, the enclosed charge within a conductor is zero which indicates that the electric field within the spherical ball is zero
On the outside, the electric field around the spherical ball is mathematically expressed as
Here a denotes a point outside the spherical ball with its value of
and k represents Coulomb's constant, valued at
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