answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pychu
3 months ago
9

there is a rusted nut we have a two spanners each of i 15 cm and 20 CM respectively which spanner is suitable to open the nut an

d why​

Physics
1 answer:
Maru [3.3K]3 months ago
8 0

Answer:

A 20 cm spanner is appropriate for loosening this nut because it allows for greater leverage when applying force to the rusted nut. Increased perpendicular distance between the force and the axis of rotation results in a larger moment.

I believe this answer will assist you.....

Thank you ☺️☺️☺️

You might be interested in
A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvat
ValentinkaMS [3465]
The focal length of the lens while in water is noted to be 150 cm, whereas in air, it measures 60 cm. To derive these values, the formula incorporates the variations in the refractive index of glass compared to that of the surrounding medium.
5 0
2 months ago
Read 2 more answers
2. An airplane traveling north at 220. meters per second encounters a 50.0-meters-per-second crosswind
Yuliya22 [3333]

The speed resulting from the plane is (3) 226 m/s

Reasoning:

We can determine the plane's resultant speed using the Pythagorean Theorem because the two speeds form a right angle (creating a right triangle).

Thus, the computation is as follows:

ResultantSpeed=\sqrt{VerticalSpeed^{2}+HorizontalSpeed^{2}}\\\\ResultantSpeed=\sqrt{(220\frac{m}{s})^{2}+50\frac{m}{s})^{2}

ResulntantSpeed=\sqrt{48400\frac{m^{2} }{s^{2} }+2500\frac{m^{2} }{s^{2} } } \\\\ResultantSpeed=\sqrt{50900\frac{m^{2} }{s^{2} }}=226\frac{m}{s}

Consequently, the plane's resultant speed is (3) 226 m/s

Have a wonderful day!

5 0
3 months ago
Mike recently purchased an optical telescope. Identify the part of the electromagnetic spectrum that is closest to the frequency
kicyunya [3294]
The electromagnetic spectrum spans from radio waves to gamma rays. The picture provided illustrates this entire spectrum. However, the optical telescope is limited to observing only the visible spectrum, which ranges from 400 nm to 700 nm. This segment reflects the colors of ROYGBIV, with red exhibiting the highest frequency and violet the lowest frequency.

8 0
3 months ago
Read 2 more answers
Other questions:
  • Hawks and gannets soar above the ground and, when they spot prey, they fold their wings and essentially drop like a stone. They
    5·1 answer
  • Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth
    11·2 answers
  • Describe a well-known hypothesis that was discarded because it was found to be untrue.earth-centered model of the universe. the
    6·1 answer
  • There are two different size spherical paintballs and the smaller one has a diameter of 5 cm and the larger one is 9 cm in diame
    13·1 answer
  • 1. Si comprimes un globo hasta reducir su volumen a un tercio de su valor original, ¿cuánto aumenta la presión en su interior?
    7·1 answer
  • An object is moving back and forth on the x-axis according to the equation x(t) = 3sin(20πt), t> 0, where x(t) is measured in
    5·1 answer
  • Two 11.5-mg balls are connected by a 28.9-cm-long insulating rod of negligible mass. One ball has a charge of +q and the other h
    12·1 answer
  • Io, a satellite of Jupiter, is the most volcanically active moon or planet in the solar system. It has volcanoes that send plume
    15·2 answers
  • Compare these two collisions of a PE student with a wall.
    15·1 answer
  • A 2-HP winch is used to raise loads of bricks up a 30 meter building. If the bricks need to get to the top of the building in 2
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!