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slavikrds
7 days ago
9

A CD has a 5% chance of being a smash hit and profiting $5.2 million, a 50% chance of being a modest success and profiting $0.9

million, and a 45% chance of being a flop and breaking even. What is the expected earnings value of the CD?
Mathematics
1 answer:
Zina [3.9K]7 days ago
5 0

P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'

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In this scenario, we start with the following expression:

58- (14) ^ 2

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Next, we have:

58- (14) ^ 2 = 58-196

The following step is to subtract the two resultant values:

58- (14) ^ 2 = -138

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Answer:

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Step One

Deduct 32 from both sides.

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Multiply each side by \frac{5}{9}.

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Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

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